Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
the statement must be true
D. <A+<D=180°
We know that the sum of all angle measures in a trapezoid is 360* (* means degrees)
Therefore we can construct the equation
(X+28)+(x)+(4x-14)+(4x-14)= 360
Now add like terms
10x = 360
And divide by the coefficient of X (aka 10)
X= 36
Answer:21
Step-by-step explanation:
x=length
x(x-6)=315
x^2-6x=315
x^2-6x-315=0
(x-21)(x+15)
x=21, x=-15
x cannot be negative so the only answer is 21
Answer:
6 units
Step-by-step explanation:
They are on the same y-point and so you just have to count the spaces between them on the x-axis.
