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scoray [572]
3 years ago
7

How do I change 13x -11y= -12 to standard form

Mathematics
1 answer:
kogti [31]3 years ago
3 0
You just solve for y.
y=<span><span><span>13/11</span>x</span>+<span>12/<span>11</span></span></span>
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HERE IS SOME INFORMATION ABOUT THE GOALS SCORED IN SOME HOCKEY GAMES.EACH GAME HAS FOUR QUARTERS
Liono4ka [1.6K]

Answer:

a) 2nd

b) 4.8

c) 4

Step-by-step explanation:

Mode is the highest frequency.

"Away" has highest frequency in the second quarter

Mean = sum/n

Sum of Home goals:

5+4+8+9 = 26

Sum of Away goals:

2+9+7+4 = 22

Total goals = 26+22 = 48

Average = 48/10 = 4.8

No. of home goals - No. of away goals

26 - 22 = 4

4 0
3 years ago
The angle between two vectors ⃗ = 2⃗ − ⃗ and ⃗⃗ = ⃗ − 3⃗ is​
ella [17]

Answer:

please post the picture of this question

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3 0
3 years ago
The height of five soldiers included 60inches,67inches,65inches and 64inches,if the mean of the five soldiers is 65inches what i
Nadya [2.5K]

Answer:

The last guy's height is 69 inches

Step-by-step explanation:

mean=sum of all numbers/number of numbers

There are 5 numbers in the set which means that 65 is the sum of all five numbers divided by 5. To reverse that we multiply 65 by 5 to get the sum of all of the numbers.

65*5=325

325 is the sum of all of the numbers so to find the missing number you add up all of the known numbers in the set and find the difference between that sum and 325.

60+67+65+64=256

325-256=69

The missing guy's height is 69 inches.

3 0
3 years ago
The difference of a number s and 6
Luda [366]

Answer:

idk

Step-by-step explanation:

What you do you have to find someone more smarter than me!

6 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
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