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DaniilM [7]
2 years ago
8

HELP ASAP PLS

Mathematics
1 answer:
s2008m [1.1K]2 years ago
6 0

I don't know what the options are in the drop-down menu but the function <em>f</em> is symmetric around the point (4,–1) which is called the axis of symmetry. (4,–1) is the minimum of the graph.

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What is 1.64 million rounded to the nearest million
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1.64 million rounded to the nearest million is 2 million.
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The Jacksons went on a 700 mile trip. On the first day they drove 6 and 2/3 hours and on the second day the drove 5 and 3/4 hour
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Answer:

Step-by-step explanation:

Total number of miles is 700.

On the first day, they drove 6 and 2/3 hours. We would convert 6 and 2/3 hours to improper fraction. It becomes 20/3 hours. On the second day, they drove 5 and 3/4 hours. Converting to improper fraction, it becomes 23/4 hours. Total number of hours that they drove during the first two days is the sum of hours driven on the first day and hours driven on the Second day. It becomes

20/3 + 23/4 = (80 + 69)/12

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3 years ago
Which shape doesn’t belong belong? Explain your reasoning.
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The trapezoid on the bottom right doesn’t belong. All the other quadrilaterals have opposite sides that are congruent.
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c= ur mom

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3 years ago
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You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
4 years ago
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