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bogdanovich [222]
4 years ago
13

Since density depends on the mass and volume of an object, we need both of these values combined in the correct way to solve for

density. Keep in mind that we may not be given the mass and volume directly, or the values may not be given in the units we want and we need to convert to the correct units before solving for density.
When converting between metric units, use the prefixes to help you determine the magnitude of a value. The prefix k indicates kilo, 1000. Therefore 1000 g = 1 kg.

A 11.0 kg iron weightlifting plate has a volume of 1400 cm3 . What is the density of the iron plate in g/cm3?

Express your answer in grams per cubic centimeter to three significant figures.
Chemistry
1 answer:
Fed [463]4 years ago
4 0

Answer:

Density=7.86g/cm³

Explanation:

To solve this exercise, we only need to <u>convert units.</u> To do so, we can use a three-step process:

  1. Identify the units that the problem gives us.
  2. Identify the units that we must report in the answer.
  3. Use the appropiate conversion factor in order to convert the units in 1.) to the units in 2.)

In this case, the units we're given are kg and cm³, and the units we must convert them into are g and cm³. Keeping in mind the conversion factor of 1000 g = 1 kg, we convert the mass of the plate:

11.0kg*\frac{1000g}{1kg}=11000 g

Then we divide the mass by the volume, that is already in cubic centimeters:

Density=\frac{11000g}{1400cm^{3}}=7.86\frac{g}{cm^{3} }

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5. Rubbing alcohol is a commonly used disinfectant and has a cooling effect when applied to the skin. The active ingredient in r
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Explanation:

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A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in
Leviafan [203]
Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
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\frac{V1}{T1} =  \frac{V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
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6 0
4 years ago
Elements that exceed the octet rule must have an _______________. unoccupied s-orbital unoccupied p-orbital unoccupied d-orbital
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7 0
4 years ago
if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass
nadya68 [22]
<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

                             = 3.268 moles

                             = 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

                             = 0.998 mole

                              = 1.0 mole

However, from the equation  2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

                       = 110.98 g CaCl₂

3 0
3 years ago
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