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bogdanovich [222]
4 years ago
13

Since density depends on the mass and volume of an object, we need both of these values combined in the correct way to solve for

density. Keep in mind that we may not be given the mass and volume directly, or the values may not be given in the units we want and we need to convert to the correct units before solving for density.
When converting between metric units, use the prefixes to help you determine the magnitude of a value. The prefix k indicates kilo, 1000. Therefore 1000 g = 1 kg.

A 11.0 kg iron weightlifting plate has a volume of 1400 cm3 . What is the density of the iron plate in g/cm3?

Express your answer in grams per cubic centimeter to three significant figures.
Chemistry
1 answer:
Fed [463]4 years ago
4 0

Answer:

Density=7.86g/cm³

Explanation:

To solve this exercise, we only need to <u>convert units.</u> To do so, we can use a three-step process:

  1. Identify the units that the problem gives us.
  2. Identify the units that we must report in the answer.
  3. Use the appropiate conversion factor in order to convert the units in 1.) to the units in 2.)

In this case, the units we're given are kg and cm³, and the units we must convert them into are g and cm³. Keeping in mind the conversion factor of 1000 g = 1 kg, we convert the mass of the plate:

11.0kg*\frac{1000g}{1kg}=11000 g

Then we divide the mass by the volume, that is already in cubic centimeters:

Density=\frac{11000g}{1400cm^{3}}=7.86\frac{g}{cm^{3} }

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The question is incomplete, here is the complete question:

Urea (CH₄N₂O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH₃) with carbon dioxide as follows: 2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l) In an industrial synthesis of urea, a chemist combines 135.9 kg of ammonia with 211.4 kg of carbon dioxide and obtains 178.0 kg of urea.

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<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

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Putting values in equation 1, we get:

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The given chemical reaction follows:

2NH_3(aq.)+CO_2(aq,)\rightarrow CH_4N_2O(aq.)+H_2O(l)

By Stoichiometry of the reaction:

2 moles of ammonia reacts with 1 mole of carbon dioxide

So, 7994.12 moles of ammonia will react with = \frac{1}{2}\times 7994.12=3997.06mol of carbon dioxide

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Thus, ammonia is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reactant is ammonia (NH_3)

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