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3 years ago

11

Glve the number of significant figures in this number: 40

2 answers:

trapecia [35]3 years ago

4 0

Answer:

the number of significant figures in this number is two because <u>non-zero digits are always significant and a final zero or trailing zero is always counted</u>

Explanation:

i hope this will help you :)

Eddi Din [679]3 years ago

3 0

Answer:

1

only 4 is the significant figure

we take tailing zeroes as significant figures only in case of decimals

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A compound consists of 18.96 g carbon, 5.53 g hydrogen, and 11.06 g nitrogen

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Explanation:

Kevlar is the high-strength polymer material. It has the following composition: 70.58% carbon, 11.76% nitrogen, 4.23% hydrogen, and 13.43% oxygen.

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Explain why titanium conducts electricity

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2 years ago

Determine ΔG° for a cell that utilizes the following reaction: Cl2(g) + 2Br–(aq) → 2Cl–(aq) + Br2(l) The standard reduction for

weeeeeb [17]

Answer:

∆G°= -55005J or -55KJ

Explanation:

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E°cell= 1.360-1.075

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From

∆G°= -nFE°cell

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4 years ago

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3 years ago

If you mix 50mL of 0.1 M TRIS acid with 60 mL of0.2 M<br> TRIS base, what will be the resulting pH?

Katyanochek1 [597]

<u>Answer:</u> The pH of resulting solution is 8.7

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

<u>For TRIS acid:</u>

Molarity of TRIS acid solution = 0.1 M

Volume of solution = 50 mL

Putting values in above equation, we get:

$0.1M=\frac{\text{Moles of TRIS acid}\times 1000}{50mL}\\\\\text{Moles of TRIS acid}=0.005mol$

<u>For TRIS base:</u>

Molarity of TRIS base solution = 0.2 M

Volume of solution = 60 mL

Putting values in above equation, we get:

$0.2M=\frac{\text{Moles of TRIS base}\times 1000}{60mL}\\\\\text{Moles of TRIS base}=0.012mol$

Volume of solution = 50 + 60 = 110 mL = 0.11 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[\text{TRIS base}]}{[\text{TRIS acid}]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of TRIS acid = 8.3

$[\text{TRIS acid}]=\frac{0.005}{0.11}$

$[\text{TRIS base}]=\frac{0.012}{0.11}$

pH = ?

Putting values in above equation, we get:

$pH=8.3+\log(\frac{0.012/0.11}{0.005/0.11})\\\\pH=8.7$

Hence, the pH of resulting solution is 8.7

6 0

4 years ago