1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oxana [17]
3 years ago
14

If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?

Chemistry
1 answer:
Igoryamba3 years ago
3 0
The correct answer is 12.2% BaO.

The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
\frac{25.8}{212}*(100) =12.2%
You might be interested in
Could a child inherit a dominant trait if neither of her parents express the dominant trait? show the cross
bearhunter [10]

Answer:

yes it does

Explanation:

I searched it up

4 0
3 years ago
Definition of phosphoric acid
miss Akunina [59]
<em>Phosphoric acid is an acid used in fertilizers and soaps.</em>

<em>                                      Hope this helps:)</em>
8 0
3 years ago
Calculate the energy of one photon of yellow light that has a wavelength of 5.89x10^-7m.​
Viktor [21]

Answer:

E = energy = ? ,

λ = Wavelength = 5.89 × 10^-7 m —> = 589 ×10 ^-9 m ,

h =Planck constant = 6.63 × 10^-34 J.s ,

f = frequency of photo/ electromagnetic radiation = c/λ ,

c = Speed of light in a vacuum = 3 × 10^8 m/s

___o___o____

E = hf \\  \\ E = h \frac{c}{λ}  \\  \\  E = 6.63 \times  {10}^{ - 34}  \frac{3 \times  {10}^{8} }{5.89 \times  {10}^{ - 7} }  \\  \\E =  \frac{6.63 \times  {10}^{ - 34} \times 3 \times  {10}^{8}  }{5.89 \times  {10}^{ - 7} }   \\  \\ E =  \frac{663 \times  {10}^{ - 36} \times 3 \times  {10}^{8}  }{589 \times  {10}^{ - 9} }  \\  \\ E =  \frac{1989 \times  {10}^{ - 28} }{589 \times  {10}^{ - 9} }  \\  \\ E = 3.37691 \times  {10}^{ - 19} J

I hope I helped you^_^

8 0
3 years ago
What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?
Leya [2.2K]

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.

n(AgNO₃) = 0,314 mol.

n(NaCl) = 14,19 g ÷ 58,4 g/mol.

n(NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.

m(AgCl) = 34,82 g.

7 0
3 years ago
Describe an example that could be an observational study
Valentin [98]
This is an observational study, because the researcher is simply observing the answers of the survey without influencing the outcome in any way. Another example of an observational study would be if a researcher was trying to determine the effects that eating strictly organic foods has on overall health.
4 0
3 years ago
Other questions:
  • A potential energy diagram to illustrate this reaction mechanism is, assuming that the overall reaction is endothermic. Label re
    13·1 answer
  • A buffer solution contains 0.306 M C6H5NH3Br and 0.418 M C6H5NH2 (aniline). Determine the pH change when 0.124 mol HCl is added
    14·1 answer
  • Do hot things, like water or magma, always rise?
    12·1 answer
  • How many significant figures are in the mass 3.0047 g?
    11·1 answer
  • Design a process for separating a mixture of salt, iron filings, and sand
    8·1 answer
  • Which of the following is not an example of temperature abuse ?
    11·2 answers
  • Which physical property of the water changes when it reaches its melting point
    8·2 answers
  • How many moles and atoms are there in 60 grams of Calcium? quick answer plz i m preparing for exams
    7·1 answer
  • What property did mosely use to organize the periodic table?​
    10·1 answer
  • What is the concentration of K+ ion in solution, in mmol/L?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!