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3 years ago

How can you tell on which two whole numbers an improper fraction would be located between on a number line?

2 answers:

3 0

The way you can tell if it is an improper fraction is when the top number is bigger then the bottom. hope that's what you are looking for :)

Margarita [4]3 years ago

3 0

The way you can tell the improper an proper fractions i think

You might be interested in

What's 2/5 - 9/10 as a fraction?

elena-s [515]

Answer:

- 1/2

Step-by-step explanation:

turn 2/5 to have the same denominator as 10

2 ( 2 ) = 4

5 ( 2 ) = 10

4/10 - 9/10

= -5/10

simplify

-5/10 = -1/2

hope this helps

4 0

3 years ago

Find the value of x. Then the measure of each angle

Shtirlitz [24]

The interior angles of a triangle must add to 180 degrees.

110+5x+2x=180
110+7x=180
7x=70
x=10

Then plug in the x value into each angle expression
5(10)=50 degrees
2(10)=20 degrees

4 0

4 years ago

Order the integers from least to greatest {-11,8,-13,-2,16}

Dovator [93]

Least to Greatest going ⬇
-13
-11
-2
8
16

3 0

3 years ago

PLEASE HELP FASTT!!!!!!!<br> In a relation, the input values can also be referred to as the_____?

nika2105 [10]

Answer:

Domain

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Simplify

OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

$\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}$

we need to simplify that

$x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)$

so we can continue

$\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}$

and we can put all together

$\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}$

3 0

3 years ago