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valentinak56 [21]

3 years ago

9

Besides the 8 planets and their satellites,what other bodies revolves around the Sun?

1 answer:

Gre4nikov [31]3 years ago

3 0

There are things like comets, asteroids, meteoroids, satellites, planets, etc. move around the sun.

Explanation:

The solar system is made up of not only planets and its satellites, but there are also other things which move around the sun.
Those are like comets, asteroids, and meteoroids.
Asteroids are also called mini planets, there are bigger ones too and they are called planetoids. The orbit the sun in their belt called asteroid belt situated in between the orbits of Mars and Jupiter.
Comets appear like snowballs which contain frozen gases, dust and rock which orbits the sun.
Meteoroids are the metallic or rocky body found the outer space. It is smaller than the asteroids and micro-scale meteoroids are the space dust.

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A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an

anyanavicka [17]

Answer:

The value of tangential acceleration $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

The value of radial acceleration $\alpha_{r} = 80 \frac{m}{s^{2} }$

Explanation:

Angular acceleration = 50 $\frac{rad}{s^{2} }$

Radius of the disk = 0.8 m

Angular velocity = 10 $\frac{rad}{s}$

We know that tangential acceleration is given by the formula $\alpha_{t} =$ $r \alpha$

Where r = radius of the disk

$\alpha$ = angular acceleration

⇒ $\alpha_{t} =$ 0.8 × 50

⇒ $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

This is the value of tangential acceleration.

Radial acceleration is given by

$\alpha_{r} = \frac{V^{2} }{r}$

Where V = velocity of the disk = r $\omega$

⇒ V = 0.8 × 10

⇒ V = 8 $\frac{m}{s}$

Radial acceleration

$\alpha_{r} = \frac{8^{2} }{0.8}$

$\alpha_{r} = 80 \frac{m}{s^{2} }$

This is the value of radial acceleration.

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4 years ago

Diego is trying to lift a piano to the second floor of his house. Diego uses a pulley system and gives a big lift to the piano.T

andreyandreev [35.5K]

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3 years ago

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Soloha48 [4]

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A proton moving at 8.00 106 m/s through a magnetic field of magnitude 1.72 T experiences a magnetic force of magnitude 7.20 10-1

gladu [14]

Answer:

19.1 deg

Explanation:

v = speed of the proton = 8 x 10⁶ m/s

B = magnitude of the magnetic field = 1.72 T

q = magnitude of charge on the proton = 1.6 x 10⁻¹⁹ C

F = magnitude of magnetic force on the proton = 7.20 x 10⁻¹³ N

θ = Angle between proton's velocity and magnetic field

magnitude of magnetic force on the proton is given as

F = q v B Sinθ

7.20 x 10⁻¹³ = (1.6 x 10⁻¹⁹) (8 x 10⁶) (1.72) Sinθ

Sinθ = 0.327

θ = 19.1 deg

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if two substances have similar physical properties such as color and texture but different in other physical properties such as

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