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frosja888 [35]
3 years ago
12

Research conducted specifically for the purpose of solving practical problems and improving quality of life is called ________

Physics
1 answer:
olganol [36]3 years ago
8 0
Applied research. For more help contact me here... [email protected]
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How does a rubber band obey the law of conservation of energy?
katovenus [111]
None of the energy is created nor destroyed
6 0
4 years ago
Energy is transmitted only in indivisible discrete quantities. True or False
alex41 [277]

Answer:

False

Explanation:

From the fact that light is emitted in portion, it does not follow that light ray is discrete in structure.

The way Einstein put it was that if a beer is always sold in pint bottles, that does not mean that beer contain of indivisible pint bottles. Yet experiments in which light  knocked electrons out of materials insistently made the point that light is absorbed only in the form of discrete portions. An emitted portion or quantum of light energy retains it's individuality in subsequent events as well.

This concept was first stated by Einstein in 1905. From the heuristic point of view that he developed light is always made up of discrete portions possessing energy and momentum.

5 0
3 years ago
A strobe-light series of pictures is taken of a red ball and a blue ball. The red ball was allowed to drop straight down, and th
blagie [28]

Answer:

The lines slope up from the red ball to the corresponding blue ball.

8 0
4 years ago
Read 2 more answers
A weather balloon is designed to expand to a maximum radius of 21 m at its working altitude, where the air pressure is 0.030 atm
dezoksy [38]

Answer:

7.65 m

Explanation:

P_1 = Initial pressure = 0.03 atm

P_2 = Final pressure = 1 atm

r_1 = Inital radius = 21 m

V_1 = Intial volume of gas = \frac{4}{3}\pi r_1^3

V_2 = Final volume of gas = \frac{4}{3}\pi r_2^3

T_1 = Initial temperature = 200 K

T_2 = Final temperature = 323 K

From ideal gas law we have

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\Rightarrow \frac{P_1\frac{4}{3}\pi r_1^3}{T_1}=\frac{P_2\frac{4}{3}\pi r_2^3}{T_2}\\\Rightarrow \frac{P_1 r_1^3}{T_1}=\frac{P_2r_2^3}{T_2}\\\Rightarrow r_2=\frac{P_1r_1^3T_2}{T_1P_2}\\\Rightarrow r_2=\left(\frac{0.03\times 21^3\times 323}{200\times 1}\right)^{\frac{1}{3}}\\\Rightarrow r_2=7.65\ m

The radius at liftoff is 7.65 m

7 0
4 years ago
A ball is thrown directly upward from a height of 3 ft with an initial velocity of 28 ​ft/sec. the function ​s(t)equalsminus16ts
borishaifa [10]

Answer:

t = 0.875 s

s_{max} = 15.25 ft

Explanation:

Position of the ball as a function of time is given as

s(t) = s_o + v_y t + \frac{1}{2}at^2

s(t) = 3 + 28 t - 16 t^2

now we know that when ball will attain maximum height then the differentiation of the position with respect to time will become zero

so we have

\frac{ds}{dt} = 0

0 = 0 + 28 - 32 t

t = 0.875 s

now the maximum height is given as

s_{max} = 3 + 28(0.875) - 16(0.875)^2

s_{max} = 15.25 ft

4 0
4 years ago
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