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iragen [17]
3 years ago
11

What particles exist within plasma that do not exist in other states?

Physics
1 answer:
34kurt3 years ago
3 0
<span>C. free electrons. Plasma is made up of atoms. The atoms have had some or all of the electrons stripped away. The nuclei are positively charged and are called ions. The ions roam freely. Gases are made up of both molecules and atoms.</span>
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•• Your roommate is working on his bicycle and has the bike upside down. He spins the 60-cm-diameter wheel, and you notice that
Y_Kistochka [10]

Answer:

v=0.57\frac{m}{s}

a_c=10.83\frac{m}{s^2}

Explanation:

We have an uniform circular motion, therefore, the pebble’s speed is given by the distance traveled in a revolution (2\pi r) and the period (T), since this is the time pebble’s takes to complete a revolution:

v=\frac{2\pi r}{T}

The period is inversely proportional to the frequency:

T=\frac{1}{f}

So, we have:

v=\frac{2\pi r}{\frac{1}{f}}\\v=2\pi rf\\

Recall that the radius is the half of the diameter and one revolution per is equal to one Hz:

v=2\pi (30*10^{-2}m)(3Hz)\\v=0.57\frac{m}{s}

The centripetal acceleration is defined as:

a_c=\frac{v^2}{r}\\a_c=\frac{(0.57\frac{m}{s})^2}{30*10^{-2}m}\\\\a_c=10.83\frac{m}{s^2}

6 0
3 years ago
Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by lamar's worm?
kumpel [21]

Complete question is;

Lamar writes several equations trying to better understand potential energy. What conclusion is best supported by Lamar’s work?

A) The elastic potential energy is the same for any distance from a reference point.

B) The gravitational potential energy equals the work needed to lift the object.

C) The gravitational potential energy is the same for any distance from a reference point.

D) The elastic potential energy equals the work needed to stretch the object

Answer:

B) The gravitational potential energy equals the work needed to lift the object.

Explanation:

In physics, we know that potential energy is the energy of a body at rest while the energy of a body in motion is known as kinetic energy.

However,the work required to lift a body from it's position of rest is equal to the Gravitational potential energy of that body.

Elastic potential energy is the one that is stored as a result of force applied to deform an elastic object. Thus, it is not equal to the work needed to stretch the object and it is also not the same for any distance from reference point.

Thus, looking at the options, Option B is correct

6 0
3 years ago
Give atleast (5) etypes of cleaning tools , equipment,supplies, and materials that you can find either in your home or school. I
ivanzaharov [21]

Answer and Explanation:

Cleaning tools, equipment, supplies, and materials that can be easily found in a school in one each are: scrub brush, sponges, buckets and brooms.

These equipments are essential to promote a clean, organized and safe environment and for this reason, they can be easily found both at school and in a home, since the cleanliness of these two places is essential for the well-being, proactivity and health of the people who attend them.

3 0
3 years ago
According to the third law of planetary motion, the period of revolution of a planet is related to the planet’s _____.
matrenka [14]
Distance from the sun.

<span>The third law of planetary motion states that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit</span>. The semi-major axis is the distance from the sun to the epicenter of the ellipse (which would be the planet in question). So, the revolutionary period is directly related to the distance of the planet from the sun.

7 0
3 years ago
Read 2 more answers
A soft drink with the properties of 10 oC water is sucked through a 4.1-mm-diameter, 0.25-m-long straw at a rate of 4.1 cm3/s.
nikdorinn [45]

Answer:

1. it is laminar flow

2. it is not fully developed

3.Re=63.156

4. entrance length is the entrance diameter which is 4.1-mm-

Explanation:

A soft drink with the properties of 10 oC water is sucked through a 4.1-mm-diameter, 0.25-m-long straw at a rate of 4.1 cm3/s.

(a) Is the flow at the outlet of the straw laminar?

(b) Is it fully developed? To explain calculate

(c) the Reynolds number and

(d) the entrance length

note te following

For&pipe&flow:&

Re&<&2100 laminar&flow&

Re&>&4000 turbulent&flow&

kinematic viscosity of water at 10 oCis 1.267E-6m^2/S

Re=vl/k.viscosity

v=q/A

q=4.1 cm3/s=4.1*10^-6m3/s

A=3.142*0.0041/4

A=0.00322m2

v=0.000318m/s

l= 0.25-m

RE=0.000318m/s*0.25/( 1.267E-6m^2/S)

Re=63.156

since re<2100 , it is laminar flow

2. it is not fully developed

3.Re=63.156

4. entrance length is the entrance diameter wic is 4.1-mm-

5 0
4 years ago
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