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nika2105 [10]
3 years ago
4

What type of operating system allows two or more programs or apps to reside in memory at the same time?

Computers and Technology
1 answer:
Crazy boy [7]3 years ago
7 0
There are two types of operating systems:

1. Single tasking operating system which allows to run only one application at a time.

2. Multitasking which allows allows two or more programs or apps to reside in memory at the same time.

The type of operating system depends on its architecture. Different architectures allow to use different amount of RAM(Random Access Memory)
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Which of the following barriers to oral communication is not the fault of the sender or receiver? being unprepared noise not pay
vredina [299]
All of the given choices are indeed common barriers to oral communication. But among them, "noise" is the only one which may not be the fault of the sender of the receiver. Noise can be generated by nearby sources independent of the sender or receiver.
6 0
3 years ago
Read 2 more answers
Question 1:
Julli [10]

Answer:

Following are the code to the given question:

#include<iostream>//header file

#include<math.h>//header file

using namespace std;

int main()//main method

{

   long long x, x1, y, y1;//defining long variable

   int count=0,i,j;//defining integer variable

   cout<<"Enter a range for x coordinates: "<<endl;//print message        

   cin>>x>>x1;//input x and x1 value                          

   cout<<"Enter a range for y coordinates: "<<endl;//print message

   cin>>y>>y1; //input y and y1 value  

   for(i = x; i <= -x1; i++)//use nested loop that tests each coordinates                                        

   {

       for(j = y; j <= y1; j++)//use nested loop that tests each coordinates

       {

           if(((2*pow(i,2)) + abs(2*i*j) + pow(j,2)) == 10000)//use if that checks condition as per the given question

           {

               cout<<"There is a planet at "<<i<<", "<<j<<endl;//  print coordinates

               count++;//incrementing count variable value                                                    

           }

       }

   }

   cout<<"Total number of planets detected are: "<<count<<endl;//print count value

   return 0;

}

Explanation:

In this code, inside the main method long "x, x1, y, and y1" and integer "count, i, and j" type variable is declared that uses a long variable to input value from the user-end.

In the next step, two nested loops have defined that test each coordinate and define if block that checks condition as per the given question and use i, j, and count variable to print value with the message.

3 0
3 years ago
Message queues allow for programs to synchronize their operations as well as transfer data. How much data can be sent in a singl
ser-zykov [4K]

The maximum size of a message queue is 16384 bytes for Linux. For IBM WebSphere MQ. this value is 4 MB.

<h3>What is the message queue?</h3>

The size of the message queue refers to the size (in bytes) that a message may have for a given operative system.

For example, the maximum value for IBM WebSphere MQ has been configured in four megabytes (4 MB).

In this case, when the message is higher than the set size (here 4 MB), then this message is returned.

Learn more about IBM here:

brainly.com/question/896257

6 0
3 years ago
Write a program that prints the following 45 pairs of numbers:
sattari [20]

Answer:

  • Code is in JAVA language. As there is no user input the logic is straightforward.
  • Below is the code along with a detailed explanation of the logic.
  • The class name is Print main save as file as the main class.

Explanation:

Program:-

public class Main{

public static void main(String args[]){

/* There are two for loops...

* First for loop runs from i=1 to i=9

* Second for loop runs from j=1 to j=i.

*

*/

for(int i=1;i<=9;i++){

for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i

/*Prints I and j next to each other*/

System.out.println(i+""+j);

}//for loop of j ends here

}// for loop of I ends here

}

}

6 0
3 years ago
Write a program to solve the selection problem. Let k = N/2. Draw a table showing the running time of your program for various v
Brums [2.3K]
So here is the code in Python:

n = 0.00 #this is a float because there are some numbers that are decimals.

while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.

You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.

4 0
3 years ago
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