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3 years ago

10

Simplify the expression -|-5 x (-7)|

1 answer:

Andrei [34K]3 years ago

7 0

Answer:

the simplified expression would be 35

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I need help with both questions on the screen. if you can only answer one thats fine too!

meriva

Answer:

11. $b = 30$

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

Substitute

$16^{2} + b^{2} = 34^{2}$

$256 + b^2 = 1156$

$b^2 = 1156-256\\b^2 = 900$

$b = \sqrt{900}$

$b = 30$

Your welcome and don't forget to say <u>Thanks</u>

7 0

3 years ago

A number is squared, then doubled and then 4 is subtracted. The result is the original number. What could the number be?

s344n2d4d5 [400]

Answer:

umm its B cause i got it right hope this helped :)

Step-by-step explanation:

8 0

3 years ago

In a group of 10 kittens, 5 are female. Two kittens are chosen at random. a) Create a probability model for the number of male

olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ± $\frac{2}{3}$ .

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

So, total number of kitten = 10

number of female kitten = 5

then, Number of male kitten = $10-5= 5$

Now total number of ways to choosing two kittens from group of 10 = $^{10} C_{2}$

= $\frac{10!}{2!\times8!}$

= $45$

for choosing (i) No male P(x=0) = P(Two female) = $\frac{^{5} C_{2}}{45}$

= $\frac{2}{9}$

(ii) 1 male P(x=1) = P(1 male and 1 female) = $\frac{^{5} C_{1}\times^{5} C_{1}}{45}$ = $\frac{25}{45}$ = $\frac{5}{9}$

(iii) 2 male P(x=2)= P(2 male) = $\frac{^{5} C_{2}}{45}$ = $\frac{2}{9}$

$x_{i}$ 0 1 2

P(X= $x_{i}$ ) $\frac{2}{9}$ $\frac{5}{9}$ $\frac{2}{9}$

(b) what is expected number of male kittens chosen ?

Expected number of male kitten E(x) = $o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}$

= $1$

(c) what is standard deviation ?

$\sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})$

No,

$Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}$

= $\frac{13}{9}$

$\sigma(x)=\sqrt{\frac{13}{9} - 1 }$ $=\sqrt{\frac{4}{9} }$

= ± $\frac{2}{3}$

6 0

3 years ago

I need to know the vertex of this parabola can someone help me ASAP

Leya [2.2K]

The vertex is located at (-1,-9)

5 0

2 years ago

3x^2-5x-4+x^3 in standard form

Zinaida [17]

Answer:

x^3 +3x^2 - 5x - 4

Step-by-step explanation:

Have to rearrange the terms into the correct format from biggest exponent to no exponent. Basically!

8 0

2 years ago