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4 years ago

A 50 coat is put on sale for 35 What percent is the decrease?

Mathematics

1 answer:

IRISSAK [1]4 years ago

4 0

so the coat went down from 50 to 35, namely 15.

if we take 50 to be the 100%, what is 15 off of it in percentage?

$\bf \begin{array}{ccll} aount&\%\\ \cline{1-2} 50&100\\ 15&x \end{array}\implies \cfrac{50}{15}=\cfrac{100}{x}\implies \cfrac{10}{3}=\cfrac{100}{x} \\\\\\ 10x=300\implies x=\cfrac{300}{10}\implies x=30$

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What do these mean?

posledela

Answer:

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Step-by-step explanation:

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I hope that this helps!

7 0

4 years ago

R+r+2r-r+4r combine like terms and solve

goldenfox [79]

R+r+2r-r+4r

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3 years ago

Students at a major university are complaining of a serious housing crunch. Many of the university's students, they complain, ha

Andrews [41]

Answer:

1) Between 12.5 miles and 21.7 miles.

2) b) 75%

3) c) 95%

4) Between 13.7 miles and 20.5 miles.

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Chebyshev Theorem:

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by $P = 100(1 - \frac{1}{k^{2}})$ .

1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles.

Within k standard deviations of the mean, and k is found when $P = 36$ . So

$P = 100(1 - \frac{1}{k^{2}})$

$36 = 100 - \frac{100}{k^2}$

$\frac{100}{k^2} = 64$

$64k^2 = 100$

$k^2 = \frac{100}{64}$

$k = \sqrt{\frac{100}{64}}$

$k = \frac{10}{8}$

$k = 1.25$

Within 1.25 standard deviations of the mean.

1.25*3.7 = 4.6 miles

17.1 - 4.6 = 12.5 miles

17.1 + 4.6 = 21.7 miles

Between 12.5 miles and 21.7 miles.

2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.

17.1 - 9.7 = 24.5 - 17.1 = 7.4 miles, so within 2 standard deviations of the mean, which is 75%, option B.

3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.

Within 2 standard deviations of the mean, by the Empirical Rule, which is 95%, option c.

4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.

Within 1 standard deviation of the mean.

17.1 - 3.4 = 13.7

17.1 + 3.4 = 20.5

Between 13.7 miles and 20.5 miles.

6 0

3 years ago

Solve the following equation for the variable x. ( 1/27 is a fraction )

igor_vitrenko [27]