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2 years ago

If your cell phone bill was 67.82 and there is a 1/20 late fee how much will your bill be with the late fee included?

Mathematics

1 answer:

almond37 [142]2 years ago

4 0

Answer:

Assuming 1/20 is a 5% late fee:

$21.211

Step-by-step explanation:

67.82 x 1/20 = 3.391

67.82 + 3.391 = 71.211

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Solve for x:<br> 4x – 7 = 8x + 33

Lera25 [3.4K]

Answer:

x = 10

Step-by-step explanation:

Hey there!

To solve this question we will use PEMDAS (order of operations)

4x−7=8x+33

Subtract 8x from both sides.

4x−7−8x=33

Combine 4x and −8x to get −4x.

−4x−7=33

Add 7 to both sides.

−4x=33+7

Add 33 and 7 to get 40.

−4x=40

Divide both sides by −4.

x= 40/-4

Divide 40 by −4 to get −10.

x=−10

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1 year ago

4. Angelina braided b inches of her hair. Brooke braided 4 less than 1/3 the number of inches Angelina braided.

Marta_Voda [28]

Answer:

Step-by-step explanation:

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2 years ago

Find the distance between the two points. (-1, 6), (2, 8) Round to the nearest hundredth

MakcuM [25]

Answer:

$d = \sqrt{13}$ or d = 3.61

Step-by-step explanation:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(2-(-1))^2+(8-6)^2}\\d= \sqrt{(3)^2+(2)^2}\\d= \sqrt{9+4}\\d= \sqrt{13}$

5 0

3 years ago

A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0

3 years ago

Gina looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one

masha68 [24]

If the shape of the room is a square, then the square root of the sum of the squares of the the two adjacent sides will give the diagonal.

i.e.

$\sqrt{17^2+17^2} = \sqrt{2(17^2)} \\ \\ = \sqrt{2(289)} = \sqrt{578} =24.04$

Since the square root of the sum of the squares of the the two adjacent sides is 24.04 and not 18.79, therefore, the shape of the room is not a square.

7 0

3 years ago