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Eva8 [605]
3 years ago
7

PLS HELP ASAP TRUE FALSE

Mathematics
1 answer:
WITCHER [35]3 years ago
8 0
I think the correct answer would most likely be true
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Students on the CARE Team are selling puppies, yes, puppies! They earn $0.40 on each puppy they sell. Their goal is to earn more
cricket20 [7]
0.4 x >= 327 Divide by 0.4
x >= 327/0.4 which is not going to be an even number.
x >= 817. 5 puppies. So they need to sell 0.5 more puppies. Better round this quickly before someone decides to do something stupid to get the extra 1/2 puppy. For us it's simple. Just add a 1/2 puppy more.

x >= 818 puppies <<<<==== answer.
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Jan needed to empty 18 gallons of water from a tub into jugs that hold 0.5 gallons of water. How many jugs did Jan need?
julsineya [31]
The answer would be 36 jugs 
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Write an equation to represent each function
Semenov [28]
1:24 and 2:20 and 3:30 and 4:16 and 5:12
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2 years ago
Write an equation of the line that is perpendicular to y=1/2x-3 and goes through the point (1,3)
Alex_Xolod [135]

Answer:

y = -2x + 5

Step-by-step explanation:

y=\frac{1}{2}x-3

Slope of this line m₁ = 1/2

Slope of the line perpendicular to this line = m₂

m₁ *m₂ = -1

m₂ = -1 *2/1 = -2

Slope  = -2; (1,3)

y- y₁ = m(x-x₁)

y - 3 = -2(x - 1)

y - 3 = -2x + 2

y = -2x +2 +3

y = -2x + 5

5 0
3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
2 years ago
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