Now, let's do the same as we did for the previous one here.
notice again, how did we get 84 for the 4th element's coefficient? well 36 * 7 / 3. and so on. And you can just expand it from there.
So, this is too vague but I'll solve for both quadratic formula and find the discriminant.
Quadratic formula: <span>x=<span>5+<span><span><span>√35 OR</span><span> </span></span>x</span></span></span>=<span>5−<span>√<span>35
Finding the discriminant: 141</span></span></span>
Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54