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3 years ago

What is the second number in this sequence? The sum of 4 consecutive integers is 354.

Mathematics

2 answers:

horrorfan [7]3 years ago

8 0

Answer:

Step-by-step explanation:

lbvjy [14]3 years ago

3 0

Answer:

Step-by-step explanation:

We have 4 numbers that sum to 354.

So, let us use a letter to represent the first consecutive number in the sum.

Let it be x.

x + (x + 1) + (x + 2) + (x + 3) = 354

We want (x + 1), the second number in the sequence.

Simplify x + (x + 1) + (x + 2) + (x + 3) = 354

x + (x + 1) + (x + 2) + (x + 3) = 4x + 6 = 354

4x + 6 = 354

4x = 354 - 6

4x = 348

x = 348/4 = 87

so x + 1 = 87 + 1 = 88

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Step-by-step explanation:

add 4 2/3 to 5/6

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3 years ago

Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu

andreyandreev [35.5K]

Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> this is the starting equation

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

Square root of negative 2x plus 1 = x + 3 she made the addtions => fine

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to plus 1 in inside the square root, this step will not help

Square root of negative 2 x = x + 2 wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root

Then, from here on all is wrong, but she made other additional mistakes.

(Square root of negative 2 x)2 = (x − 4)2 −2x the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x

Later she made a mistake changing the sign of -8x to +8x

Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

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3 years ago

Read 2 more answers

I'll give brainliest to the correct answer! (Picture below)

Lina20 [59]

9514 1404 393

Answer:

D. 7

Step-by-step explanation:

The equation is ...

x = a(y +1)² -3

For the point (x, y) = (4, 0), we have ...

4 = a(0 -1)² -3

7 = a . . . . . . . . . . . . add 3, simplify

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3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

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A. 120 millimeters.

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