The square root of a number is greater than the square of the number. For what set of numbers is this true? (0, 1) [0, 1] [1, ꝏ)

Question

worty [1.4K]

4 years ago

5

The square root of a number is greater than the square of the number. For what set of numbers is this true? (0, 1) [0, 1] [1, ꝏ)

(1, ꝏ)

Mathematics

2 answers:

vredina [299] · Answer 1 · 2021-12-25T15:31:35+03:00

Answer:

(0,1)

Step-by-step explanation:

If you plug in f(x)= $\sqrt{x}$ and g(x)= $x^{2}$ into the calculator, you will find that from 0 to 1 that f(x) is rises above g(x). The parentheses are not [ ] because the question is not asking for <em>greater than or equal to.</em>

bezimeni [28] · Answer 2 · 2021-12-25T17:13:33+03:00

bezimeni [28]4 years ago

4 0

Answer:

(0,1)

Step-by-step explanation: