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yaroslaw [1]
2 years ago
15

Solve: 7(2)^x=224 ( help pls )

Mathematics
2 answers:
AfilCa [17]2 years ago
6 0

Answer:

5

Step-by-step explanation:

Original equation:

7(2)^x=224

Divide both sides by 7

2^x=32

Rewrite in log

log_232=x

You can do mental math to realize this equals 5, or plug this into your calculate (if it allows you to set the base), but if you can't do either, you can use the change of base formula:

log_ba=\frac{log (a)}{log(b)}

You get:

log_232=\frac{log(32)}{log(2)}

When you calculate using a calculator you should get 5

Taya2010 [7]2 years ago
5 0

Answer: x = 5

Step-by-step explanation:

7(2)^x=224

start by dividing 7 from both sides

\frac{7(2)^x}{7} =\frac{224}{7}

2^x=32

take the log of both sides

log(2^x) = log(32)

move the x to the left of the log

xlog(2) = log(32)

divide both sides by log(2)

x=\frac{log(32)}{log(2)}

use change-of-base formula

\frac{log(a)}{log(b)} =logx_{b} (a)

x = log_{2} (32)

since 2^5 = 32, x = 5

<h2>Hope this helped :)</h2>
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