All categories

3 years ago

Plz help ASAP giveing brain list thx and u get points

Mathematics

2 answers:

Alex787 [66]3 years ago

7 0

The correct answer would be A

MariettaO [177]3 years ago

3 0

Answer would be A because it’s to long explain I can send you the sheet with the work on it if u want

You might be interested in

Please help!!!! I will give brainly!

yuradex [85]

Answer: Q#1:0.26

Step-by-step explanation: just round it up

3 0

3 years ago

Read 2 more answers

Whats 1 plus 1 pls help im lonley

VLD [36.1K]

Answer: im lonely 2 but the answer is shrek!

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I NEED HELP PLEASE! If you can help me with this you amazing! Thank you

krek1111 [17]

Answer:

$a=-3$

Step-by-step explanation:

we have

$a-2=\frac{3+6a}{3}$

Solve for a

That means ----> Isolate the variable a

Factor 3 in the numerator right side

$a-2=\frac{3(1+2a)}{3}$

Simplify right side

$a-2=1+2a$

subtract a both sides

$a-2-a=1+2a-a$

$-2=1+a$

subtract 1 both sides

$-2-1=1+a-1$

$-3=a$

Rewrite

$a=-3$

6 0

2 years ago

Can someone please tell me if this is correct if it’s not can u tell me what’s the correct answer

bearhunter [10]

Answer:

2. option D and 3. option A

Step-by-step explanation:

2. 7 + y = 30

7 - 7 + y = 30 - 7

y = 23

3. w - 32 = 55

w - 32 + 32 = 55 - 32

w = 87

Basically the answers you choose are right. Hope this helps, thank you :) !!

8 0

2 years ago

Calculating area of rectangle

PSYCHO15rus [73]

Answer:

$Area = 216.108cm^2$ --- You

$Area = 216.940cm^2$ --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

$Length = 20.70cm; Width =10.44cm$

Another students'

$Length = 20.74cm; Width =10.46cm$

Solving (a): The area

Area is calculated as:

$Area = Length * Width$

For you

$Area = 20.70cm * 10.44cm$

$Area = 216.108cm^2$

For the other student

$Area = 20.74cm * 10.46cm$

$Area = 216.940cm^2$

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0

3 years ago