Question

Which line represents the linear equation

Answer 1

hopefully the photo helps

Answer 2

Answer:

Pat a) The graph in the attached figure

Part b)  $y=(4/3)x-5$

The slope is  $m=(4/3)$

The y-coordinate of the y-intercept is  $b=-5$

Step-by-step explanation:

Part a) Which line represents the linear equation $-3y=15-4x$?

To graph the linear equation find the intercepts

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

$-3y=15-4(0)$

$-3y=15$

$y=-5$

The y-intercept is the point $(0,-5)$

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

$-3(0)=15-4x$

$4x=15$

$x=15/4=3.75$

The x-intercept is the point $(3.75,0)$

Plot the intercepts to graph the linear equation

see the attached figure

Part b) Rewritten in slope-intercept form

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

we have

$-3y=15-4x$

convert to slope intercept form

isolate the variable y

$3y=4x-15$

$y=(4/3)x-5$

The slope is  $m=(4/3)$

The y-coordinate of the y-intercept is  $b=-5$