Sucks for you. nerdddddddddddddddddddddddddd
part A
if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.
part B
so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3. 22 got damaged.
![\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bdamaged%20books%20at%20half-price%7D%7D%7B%2822%5Ccdot%2014.994%29%5Ccfrac%7B1%7D%7B2%7D%5Cimplies%20164.934%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bdamaged%20books%20at%20one-third%20price%7D%7D%7B%2822%5Ccdot%2014.994%29%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20109.956%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20164.934%20-%20109.956%20%3D%2054.978~%5Chfill)
part C
![\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BFirst%20Day%7D~%5Chfill%20%5Cstackrel%7Bhardcover%7D%7B3%2824.99%29%7D%2B%5Cstackrel%7Bpaperback%7D%7B8%2814.994%29%7D%2B%5Cstackrel%7Bdamaged%7D%7B3%5Cleft%28%2014.994%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%7D%20%5Cimplies%20217.413%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7BSecond%20Day%7D~%5Chfill%20%5Cstackrel%7Bhardcover%7D%7B4%2824.99%29%7D%2B%5Cstackrel%7Bpaperback%7D%7B5%2814.994%29%7D%2B%5Cstackrel%7Bdamaged%7D%7B8%5Cleft%28%2014.994%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%7D%5Cimplies%20234.906%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cboxed%7B17.493%7D)
I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.
Answer:
D
Step-by-step explanation:
Solution:-
The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:
f ( x ) = sin ( w*x ± k ) ± b
Where,
w: The frequency of the cycle
k: The phase difference
b: The vertical shift of center line from origin
We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).
We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.
The resulting sinusoidal waveform can be expressed as:
f ( x ) = sin ( 2x ) ... Answer
Answer:
O g(x) is shifted 4 units left and 6 units down from f(x).
Step-by-step explanation:
O g(x) is shifted 4 units left and 6 units down from f(x).
Answer:
a=3, b=3, c=5, d=2
Step-by-step explanation:
prime factorization of 600: 
× 3 × 
