The answer to your question is 2
So we are trying to find the numerator of 42 in relation of 6/7.
42 divided by 7= 6 So 6 x 6 from the numerator of 6/7 = 36.
So 6/7 written as a fraction with a denominator of 42 is 36/42.
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
Answer:
k = 9.6
Step-by-step explanation:
When dealing with inverse variation, the two variables vary in opposite directions. This means that as the first variable increases, second variable decreases and as the first variable reduces,the second variable increases.
Y varies inversely with x.
So as y increases, x reduces and as y reduces, x increases.
We would proceed by introducing a constant of variation, k
y = k/x
From the information given,
The constant of variation = k
The value if x = 6.4
The value of y = 1.5
To find the value of k
y = k/x
k = yx = 1.5 × 6.4
k = 9.6
Answer:
102
Step-by-step explanation:
