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3 years ago

Which relationship describes angles 1 and 2?

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

1 and 2 are vertical angles

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Can you please help me fast

marishachu [46]

Answer:

126 degrees

Step-by-step explanation:

Angle 4 is supplemnetary to angle 3..which means both of their angles add up to 180 degrees

We can take the angle of 3 whihc is 54 degrees and subtract that from 180 to determine angle 4:

180 - 54 = 126

Angle 4 is 126 degrees

8 0

2 years ago

How do I do this please help

Fittoniya [83]

The answer is c because when it's an inequality, x=4 that means that you need to put it in a numberline and since the numbers to your left will always be less than 4 the shaded part is on the right.

3 0

3 years ago

I went to a restaurant and gave the waitress a $15 tip. If the tip was 20% of the dinner how much was the dinner?

prohojiy [21]

Answer:

Dinner only: $75

Dinner and Tip: $90

Step-by-step explanation:

If the tip was $15, and the tip was 20% of the price of dinner, then dinner was $75.

You can find this out by doing 15/20%, which should give you 75.

If the question requires you to add up the price of dinner and the tip, then the total price would be $90

7 0

3 years ago

I purchase x pizzas, y 12-packs of soda, and z cupcakes for a party. If each pizza costs $7.50, each 12-packs of soda costs $3.2

svetlana [45]

Answer:

t=7.50x+0.75z+3.25y

8 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago