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Basile [38]
3 years ago
15

Which relationship describes angles 1 and 2?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

1 and 2 are vertical angles

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Can you please help me fast
marishachu [46]

Answer:

126 degrees

Step-by-step explanation:

Angle 4 is supplemnetary to angle 3..which means both of their angles add up to 180 degrees

We can take the angle of 3 whihc is 54 degrees and subtract that from 180 to determine angle 4:

180 - 54 = 126

Angle 4 is 126 degrees

8 0
2 years ago
How do I do this please help
Fittoniya [83]
The answer is c because when it's an inequality, x=4 that means that you need to put it in a numberline and since the numbers to your left will always be less than 4 the shaded part is on the right.
3 0
3 years ago
I went to a restaurant and gave the waitress a $15 tip. If the tip was 20% of the dinner how much was the dinner?
prohojiy [21]

Answer:

Dinner only: $75

Dinner and Tip: $90

Step-by-step explanation:

If the tip was $15, and the tip was 20% of the price of dinner, then dinner was $75.

You can find this out by doing 15/20%, which should give you 75.

If the question requires you to add up the price of dinner and the tip, then the total price would be $90

7 0
3 years ago
I purchase x pizzas, y 12-packs of soda, and z cupcakes for a party. If each pizza costs $7.50, each 12-packs of soda costs $3.2
svetlana [45]

Answer:

t=7.50x+0.75z+3.25y

8 0
3 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
1 year ago
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