Question

17 children go on a fairground ride. each car takes 3 children. how may cars are needed for everyone to ride?

Answer 1

Answer:

6 cars

Step-by-step explanation:

1 car can carry 3 children

Therefore, X cars will carry 17 children.

x cars = 17/3 = 6 ( 5 cars is needed for 15 children and the remaining 2 children will need and extra car. Making a total of 6cars

Answer 2

1 car can take 3 children.

17 children?

$17 \div 3 = 5.78$

There cannot be 5.78 cars. So, six cars will be needed (five cars will hold 3 children each but the sixth one shall hold 2 only since there are 17 children).