All categories

3 years ago

The length of side X is 36.25 cm to the nearest hundredth of a centimeter what is the length of y

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

Answer:

<h3>The length of y is 62.82 cm.</h3>

Step-by-step explanation:

We are given a right triangle with an angle 30°.

Opposite side of angle 30° is x and adjacent side is y.

Also, given length of side x=36.25 cm.

In order to find the value of y, we need to apply tangent trigonometrical ratio.

We know,

$tan \theta =\frac{Opposite \ Side}{Adjacent \ Side}$

Therefore,

$tan \theta =\frac{x}{y}$

Plugging values of $\theta =30^o$ and x=36.25, we get

$tan 30^o=\frac{36.25}{y}$

Plugging value of $tan 30^o=0.577$ in above equation, we get

$0.577=\frac{36.25}{y}$

On multiplying both sides by y, we get

$0.577\times y=\frac{36.25}{y}\times y$

0.577y=36.25

Dividing both sides by 0.577, we get

$\frac{0.577y}{0.577} =\frac{36.25}{0.577}$

y=62.82

<h3>Therefore, the length of y is 62.82 cm.</h3>

You might be interested in

What is the measure of each angel?? Plzzz Hurry! will give 60 points:))))))

V125BC [204]

Answer:

????????????????????????

8 0

3 years ago

Read 2 more answers

three friends go to a book fair . alvin speends 2.60 . prabhjot spends 4 times as much as alvin . stephanie spends 3.45 less the

blsea [12.9K]

Answer:

6.95

Step-by-step explanation:

to find how much stephanie spends for first we will find how much probhjot spends and then subtract 3.45 dollars from that value alvin spends 2.60 dollars

prohbjot spends 4 times as much as alvin or

4× 2.60=10.4

so prohbjot spends 10.4 dollars

stephanie spends3.45 dollars less than prohbjot or

10.4 -3.45 =6.95

so stephanie spends 6.95 dollars

7 0

3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

3 years ago

Four times the largest of three consecutive odd integers is 36 more than the sum of the other

erica [24]

If you know how to solve word problems involving the sum of consecutive even integers, you should be able to easily solve word problems that involve the sum of consecutive odd integers. The key is to have a good grasp of what odd integers are and how consecutive odd integers can be represented.

Odd Integers

If you recall, an even integer is always 22 times a number. Thus, the general form of an even number is n=2kn=2k, where kk is an integer.

So what does it mean when we say that an integer is odd? Well, it means that it’s one less or one more than an even number. In other words, odd integers are one unit less or one unit more of an even number.

Therefore, the general form of an odd integer can be expressed as nn is n=2k-1n=2k−1 or n=2k+1n=2k+1, where kk is an integer.

Observe that if you’re given an even integer, that even integer is always in between two odd integers. For instance, the even integer 44 is between 33 and 55.

6 0

3 years ago

Estimate the total cost of 31 televisions at £196.50 each and 19 DVD players at £50.99 each

Gwar [14]

Answer:

Solution,

Cost of one television=£196.50

cost of 31 televisions:

 $= 196.50 \times 31 \\ = 6091.5$ 

Cost of one DVD player=£50.99

Cost of 19 DVD player:

 $= 50.99 \times 19 \\ = 968.81$ 

Now,

Total cost

= cost of 31 televisions + cost of 19 DVD player

=6091.5+968.81

=£7060.31

Hope this helps...

Good luck on your assignment..

3 0

4 years ago

Read 2 more answers