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4 years ago

15

which of these is a unique property of bases a- contains carbon b- feels slippery c- conducts electricity in solution or d- tast

es sour

2 answers:

vazorg [7]4 years ago

8 0

B is the answer. Hope this helps

Tju [1.3M]4 years ago

7 0

A base taste bitter, not sour, so not D, But a base is slippery, so B.

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When the ideal gas law constant 0.0821 is used, what unit of pressure should be used in the ideal gas law calculation?

Julli [10]

The pressure unit is in atmospheres or atm. To confirm this from the ideal gas equation:

R = VP/nT

plugging in the standard values of pressure, temperature and molar volume,

R = (22.4L/mo)l(1atm)/(273.15K) = 0.0821

7 0

3 years ago

Calculate the energy, in joules, to heat two cubes (silver and copper), each with a volume of 10.0cm, from 15 C to 25 C

Julli [10]

Answer:

For Silver , The heat absorbed = <u>246.75 J</u>

For Copper , The heat is =<u> 343.42 J</u>

<u />

Explanation:

The change in temperature is calculated by:

$\Delta T=T_{2}-T_{1}$

T2 = 25 C

T1 = 15 C

$\Delta T=25-15$

$\Delta T=10^{0}C$

The energy in Joules can be calculated using :

$q=mc\Delta T$

here , m = mass of the substance

c = the heat capacity

q = heat absorbed / released

We need to calculate the mass , In order to determine the value of "q".

<u>Calculation for Silver :</u>

<u><em>The mass is calculated from the density of the element.</em></u>

density of Silver = 10.5 g/ml (look at the table of density)

Volume of Cube = 10 cm^3 (given)

1 cm^3 = 1 mL

10 cm^3 = 10 mL

The mass can be calculated using the formula:

$mass = density\times Volume$

$mass = 10.5\times 10$

$mass = 105grams$

Insert the value of m , c, T in the equation.

for Silver the value of "c"= 0.235 J/gC (Look at the table)

$q=mc\Delta T$

$q=105\times 0.235\times 10$

<u> $q=246.75J$ </u>

<u>Calculation for Copper:</u>

Again first calculate the mass of Copper.

Density of Copper = 8.92 g/ml

Volume = 10 mL

$mass = density\times Volume$

$mass = 8.92\times 10$

$mass = 89.2grams$

Insert the value of m , c, T in the equation.

for Silver the value of "c"= 0.385 J/gC (Look at the table)

$q=mc\Delta T$

$q=89.2\times 0.385\times 10$

<u> $q=343.42J$ </u>

8 0

3 years ago

The polarity of the HCL molecule is due to the

slega [8]

Answer:Explanation: Polarity in a molecule arises due to unequal sharing of electrons. Hydrogen atom has one electron whereas chlorine atom has 17 electrons. Thus, in order to complete their octet both H and Cl will share an electron with each other.

Explanation:

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4 years ago

_KOH + _H₂PO4 → _K₂PO4 + _H₂O

Hunter-Best [27]

Answer:

2KOH+H2PO4--K2PO4+4H2O

3 0

3 years ago

Calculate your percent yield for the bromination of cis-stilbene. [Note: Assume that stilbene is the limiting reagent. You must

evablogger [386]

Answer:

See explanation below

Explanation:

To calculate any percent yield of a reaction you need to provide, the theorical data and the experimental data, which you are not providing.

I will do an example with some values I found on another place to explain to you how to do it. You then, replace the data you have and follow the same procedure.

Let's suppose we have the following data of the stilbene:

density: 1.0111 g/mL

volume used: 0.3 mL

Molecular weight: 180.25 g/mol

Now, we use 0.3 mL of cis stilbene to do a reaction with acid and bromine to produce the 1,2-dibromo-1,2-diphenylethane.

The problem stated that the cis stilbene is the limiting reactant, therefore, the moles consumed of stilbene, would be the moles produced of the final product.

With the density let's calculate the mass of stilbene, and then, with the molecular weight, the moles:

d = m/V ---> m = d*V

m = 1.011 * 0.3 = 0.3033 g

moles = 0.3033 / 180.25 = 0.0017 moles

These obtained moles would be the moles of the final product too, because stilbene is the limiting reactant so:

moles of product = 0.0017 moles

Let's calculate the mass:

Molecular weight of 1,2-dibromo-1,2-diphenylethane = 339.8 g/mol

m = 0.0017 * 339.8 = 0.5776 g

This would be the theorical mass obtained in the experiment. Now, let's suppose we obtained a mass of 0.4158 g. This is the actual yield of the reaction, so the percetn yield would be:

%yield = Exp yield / theo yield * 100

Replacing:

%yield = 0.4158/0.5776 * 100

<em>%yield = 71.99 %</em>

This would be the %yield of the bromination. All you have to do now, is replace your theorical and experimental data and you should get to the final and accurate yield.

7 0

4 years ago