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Ostrovityanka [42]
2 years ago
9

Help please hurry lots of points

Chemistry
1 answer:
andrey2020 [161]2 years ago
7 0
I think ionic hope it helps
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Newtons first law second law and third law <br><br> help
Romashka [77]

Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

hope this helps

7 0
3 years ago
A farmer is analyzing cross sections of his land to determine where to build a well.
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Jahsjavana Shabbat a
7 0
3 years ago
Identify a cation. Group of answer choices an atom that has lost a proton. an atom that has gained an electron an atom that has
pshichka [43]

Answer: An atom that has gained an electron.

Explanation:

The number of protons in an atom cannot change except for some exceptional circumstances.

Cations (or metal ions) are formed when atoms lose electrons, as they want to form a complete outer electron shell to become as stable as possible.

For example, potassium is a 1+ ion, because it has one electron in its outer shell (and in group one). Therefore, to become more stable that electron is lost to become an ion or cation. As one electron is lost, the potassium cation charge is 1+ as the charge of an electron is 1-.

3 0
2 years ago
What will happen to the equilibrium between carbonic acid and bicarbonate if I add a strong base to this system?
Helen [10]

Answer:

The equilibrium will shift in forward direction.

Explanation:

The equilibrium between the carbonic acid and bicarbonate ion is shown below as:

H₂CO₃ (aq) ⇔ H⁺(aq) + HCO₃²⁻(aq)

According to Le Chatelier's Principle, the change in any state of the equilibrium say temperature, volume, pressure, or the concentration, the equilibrium will oppose these changes and will shift in such a way that the effect cause must be nullified.

<u>If a strong base is added to the equilibrium, the base will accept hydrogen ions which are formed in the right side of the equilibrium. Thus, there will be less hydrogen ions present and to compensate this effect, the equilibrium will shift in forward direction.</u>

3 0
2 years ago
You have 1 liter of a freshly prepared 0.1 m sucrose (molecular mass 342) solution, which means ________.
iris [78.8K]

1 liter of 0.1 M sucrose solution means that there is 34.2 g of sucrose dissolved in water to make a 1 liter solution. This also means that there are 6.022 × 10²² molecules of sucrose in this solution.  

<h3>FURTHER EXPLANATION </h3>

Molarity is a unit of concentration which describes the number of moles of solute dissolved per liter of a solution. It is calculated using the equation below:

molarity = \frac{moles \ of \ solute}{volume \ of \ solution}

Molarity is expressed with the unit mol/L or M (read as “molar”).  It is a very useful unit of concentration because many quantitative information about the solution can be obtained from this value.

<u>Mass of Solute from Molarity</u>

From the molarity of a solution, the equivalent mass of the solute used to prepare the solution may be obtained with the use of the formula mass (or molecular mass) through the equation:

molarity = \frac{\frac{mass\ of \ solute}{formula \ mass}}{volume \ of \ solution}\\\\mass \ of \ solute \ = molarity \times \ volume \ of \ solution \times formula \ mass

<u>Number of Representative Particles from Molarity</u>

Moreover, the number of molecules of solute present in the solution may also be obtained using the molarity and Avogadro's number.

molarity = \frac{moles \ of \ solute}{volume \ of \ solution}\\\\no. \ of \ representative \ particles \ = molarity \times volume \times 6.022 \times 10^{23} \ representative \ particles

For this problem, the mass of the solute dissolved in the solution and the number of sucrose molecules may be obtained from the molarity of the solution.

<em>Mass of Sucrose</em>

mass \ of \ sucrose \ = 0.1 \ \frac{mol}{L} \times 1 \ L \times \frac{342 \ g \ sucrose}{1 \ mol}\\\\\boxed {\boxed {mass \ of \ sucrose = 34.2 \ g \ sucrose}}

<em>Number of Sucrose Molecules</em>

<em>no. \ of \ sucrose \ molecules \ = 0.1 \frac{mol}{L} \times 1 \ L \times \frac{6.022 \times 10^{23} \ sucrose \ molecules}{1 \ mol}\\\\\boxed {\boxed {no. \ of \ sucrose \ molecules \ = 6.022 \times 10^{22} \ molecules}}</em>

<h3>LEARN MORE</h3>
  1. Ways of Expressing Concentration brainly.com/question/12936072
  2. Empirical Formula brainly.com/question/8516072

<em>Keywords: molarity, molar concentration</em>

8 0
3 years ago
Read 2 more answers
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