Answer:
1) The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.
2) The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 0.045 mol/L.s.
Explanation:
<em>3NO(g) → N₂O(g) + NO₂(g).</em>
The rate of the reaction = -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt = Δ[NO₂]/Δt.
Given that: Δ[N₂O]/Δt = 0.015 mol/L.s.
<em>1) The rate of the overall reaction is?</em>
The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L.s.
<em>2) The rate of change for NO is?</em>
The rate of change for NO = - Δ[NO]/Δt.
∵ -1/3 Δ[NO]/Δt = Δ[N₂O]/Δt.
<em>∴ The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt </em>= 3(0.015 mol/L.s) = <em>0.045 mol/L.s.</em>
All the information is answered/given in the paragraph except that the study doesn’t show cells in their natural habitat!
700 L hope this helped you
This reaction is double replacement because two ionic compounds are exchanged, making two new ionic compounds.
