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Alex_Xolod [135]
3 years ago
5

The maximum contaminant level of copper (Cu) in drinking water as set by the the Environmental Protection Agency (EPA) is 0.0013

g⋅L−1 . Express this concentration in parts per million (ppm). Assume the density of water is 1.00 g/mL .
Chemistry
2 answers:
lozanna [386]3 years ago
8 0

Answer:6.6 on edg

Explanation:

pochemuha3 years ago
7 0

Given that the maximum contaminant level of copper in potable water according to the Environmental Protection Agency (EPA) is 0.0013g/L

That means 0.0013 g of Copper can be present in 1 L water.

ppm(parts per million) is equivalent to the concentration of mg/L

1 ppm = 1 mg/L

We can convert 0.0013 g/L to mg/L in order to get the concentration in ppm.

Converting 0.0013 g/L to mg/L:

0.0013\frac{g}{L} *\frac{1000mg}{1g} =1.3mg/L

1.3 mg/L = 1.3 ppm

Therefore, 0.0013g/L can be expressed as 1.3 ppm


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How lead and iodine compound formed
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These are dissolved in water to form colourless solutions, and then mixed together. This mixing leads to a double displacement reaction, essentially resulting in the metals 'swapping' their places in the two compounds, producing lead (II) iodide, and potassium nitrate.
3 0
2 years ago
How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102
Ede4ka [16]

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles

1 mole of hydrogen (H_2) = 2\times 6.023\times 10^{23}=12.05\times 10^{23} atoms

17.5 mole of hydrogen (H_2) = \frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25} atoms

There are 2.12\times 10^{25} atoms of hydrogen are there in

35.0 grams of hydrogen gas.

8 0
3 years ago
Plz help me I am timed
Eddi Din [679]

Answer:

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Explanation:

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3 years ago
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Question: Draw a valid Lewis structure for the molecule CH3NO in which there are no nonzero formal charges on any of the atoms.
iVinArrow [24]

The mentioned molecule with formula, CH₃NO where no bond is found between N and O can be depicted as formamide is shown in the attachment below.  

The formal charges = Number of valence electrons for the atom (V) - the number of electrons in lone pairs (N) - 1/2 (number of electrons in bond pairs, B)

FC = V - N - B/2

Thus, there is a need to calculate valence electrons, electrons in lone pairs, and the number of electrons in bond pairs for each atom in the mentioned molecule.  

V or valence electrons on C = 4e, on H = 1e, on N = 5e, and on O = 6e.  

N or electrons in lone pairs on C = 0e, on H = 0e, on N = 2e, and on O = 4e.  

B or number of electrons in bond pairs for C = 8e, for H = 2e, for N = 6e, and for O = 4e.  

Thus, the formal charges for each will be,  

C = 4 - 0 - (8/2) = 0

H = 1 - 0 - (2/2) = 0

N = 5 - 2 - (6/2) = 0

O = 6 - 4 - (4/2) = 0

Lewis dot structure for the given molecule is given in the attachment below:


3 0
3 years ago
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If you have 3 moles of a gas at a pressure of 2.5 atm and a volume of 8 liters, what is the temperature?
fomenos

Answer:

d

Explanation:

pv=nrt

2.5×1.01×10^5×8×10^-3=3×8.31×T

T=

3 0
2 years ago
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