The maximum contaminant level of copper (Cu) in drinking water as set by the the Environmental Protection Agency (EPA) is 0.0013
2 answers:
Given that the maximum contaminant level of copper in potable water according to the Environmental Protection Agency (EPA) is 0.0013g/L
That means 0.0013 g of Copper can be present in 1 L water.
ppm(parts per million) is equivalent to the concentration of mg/L
1 ppm = 1 mg/L
We can convert 0.0013 g/L to mg/L in order to get the concentration in ppm.
Converting 0.0013 g/L to mg/L:
1.3 mg/L = 1.3 ppm
Therefore, 0.0013g/L can be expressed as 1.3 ppm
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Answer:
A
Explanation:
To answer this, we need to use Gay-Lussac's law, which states that:
, where P is pressure and T is temperature
The initial pressure we're given is 4.5 atm (so P1 = 4.5) and the temperature is 45.0°C; however, we need to change Celsius to Kelvins, so add 273 to 45.0: 45.0 + 273 = 318 K (so T1 = 318).
The final pressure is what we want to find, but we do know the final temperature is 3.1°C. Converting this to Kelvins, we get: 3.1 + 273 = 276.1 K, which means T2 = 276.1.
Plug these values in:
Multiply both sides by 276.1:
≈ 3.9 atm
The answer is thus A.