Question

The maximum contaminant level of copper (Cu) in drinking water as set by the the Environmental Protection Agency (EPA) is 0.0013 g⋅L−1 . Express this concentration in parts per million (ppm). Assume the density of water is 1.00 g/mL .

Answer 1

Answer:6.6 on edg

Explanation:

Answer 2

Given that the maximum contaminant level of copper in potable water according to the Environmental Protection Agency (EPA) is 0.0013g/L

That means 0.0013 g of Copper can be present in 1 L water.

ppm(parts per million) is equivalent to the concentration of mg/L

1 ppm = 1 mg/L

We can convert 0.0013 g/L to mg/L in order to get the concentration in ppm.

Converting 0.0013 g/L to mg/L:

$0.0013\frac{g}{L} *\frac{1000mg}{1g} =1.3mg/L$

1.3 mg/L = 1.3 ppm

Therefore, 0.0013g/L can be expressed as 1.3 ppm