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Leto [7]
2 years ago
9

2. Describe briefly of some ways these organisms might interact with each other. (5 points)

Chemistry
1 answer:
Reika [66]2 years ago
6 0
Individual organisms live together in an ecosystem and depend on one another. Other organisms have to get their food by eating other organisms.
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An object is uniformly accelerated from rest to a speed of 35 meters per second in 7 seconds. The acceleration of the object is
gavmur [86]
Its 5m/s because you have to find out how many meters for one second so you divide
35/7=5 so that's your answer
3 0
3 years ago
Read 2 more answers
This malleable metal has an atomic number of 79
bulgar [2K]
The malleable metal on the periodic table with the atomic number of 79 is gold
7 0
3 years ago
Draw the product formed when oleic acid is hydrogenated.
lesya [120]

Oleic acid belongs to class of alkene and in alkenes, addition of H-H across C=C that is carbon carbon double bond results in the formation of alkane as a product in the presence of specific catalyst such as nickel, palladium and platinum.  The reaction is said to be hydrogenation reaction.

Oleic acid (C_{17}H_{33}COOH) consist of 17 carbon atoms attached to 33 hydrogen atoms with one double bond between two carbon atoms and one carboxylic group i.e.(-COOH). When oleic acid is hydrogenated or reacts with hydrogen in the presence of catalyst, then the carbon carbon double breaks by the addition H-H and alkane product i.e. stearic acid  (C_{17}H_{35}COOH) is formed.

The chemical reaction is shown in the image.

7 0
3 years ago
A-potassium<br>B-lead<br>C-iron<br>D-magnesium<br>E-zinc<br>​
viktelen [127]

The unknown substance : Lead

<h3>Further explanation</h3>

Given

Density of element

mass of unknown substance = 40 g

volume = 3.5 cm³

Required

The density of unknown substance

Solution

Density is the ratio of mass per unit volume  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

Input the value to find the density of an unknown substance :

ρ = 40 g : 3.5 cm³

ρ = 11.43 g/cm³

If we look at the table, the substance which has a density of 11.43 is Lead

6 0
3 years ago
Una piedra es lanzada horizontalmente desde la azote de un edificio de 30 metros de altura, con una velocidad de 12 m/s. Hallar
drek231 [11]

Answer: La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

Explanation:

Ok, tenemos 2 sistemas de ecuaciones para este problema.

Primero, el vertical:

La aceleración es la aceleración gravitatoria, entonces:

a = -9.8m/s^2

para la velocidad podemos integrar sobre el tiempo y obtenemos

v = (-9.8m/s^2)*t + v0

donde v0 es la velocidad inicial, pero la velocidad inicial es solo horizontal, entonces v0 = 0.

Para la posición integramos de vuelta:

p = (1/2)*(-9.8m/s^2)*t^2 + p0

donde p0 es la posición inicial, en este caso, 30m

p = (-4.9m/s^2)*t^2 + 30m

la piedra va a llegar al piso cuando la posición vertical sea igual a 0m

p = 0m =  (-4.9m/s^2)*t^2 + 30m

de aca podemos despejar el tiempo que la piedra tarda en llegar al suelo.

t = √(30/4.9) segundos = 2.47 s.

Ahora, las ecuaciones para el movimiento horizontal son:

Aceleración nula, pues no hay ninguna fuerza actuando en la dirección horizontal.

a = 0

para la velocidad, integramos sobre el tiempo:

v = 0*t + v0 = v0

donde v0 es la velocidad inicial, en este caso, es 12m/s

v = 12m/s

para la posición integramos de vuelta:

p = 12m/s*t + p0

en este caso podemos asumir que estamos inicialmente en el punto x = x0, asi que la posición inicial es p0 = x0.

p = 12m/s*t + x0

entonces, si queremos calcular la distancia entre la base del edificio y el punto donde cae la piedra, tenemos que calcular:

D = p(2.47s) - p(0s)

D = 12m/s*2.47s + x0 - (12m/s*0s + x0)

D = 29.64m

La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

3 0
3 years ago
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