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3 years ago

How big is the solar system compared to universe

Chemistry

1 answer:

murzikaleks [220]3 years ago

8 0

Answer:

You are one of the billions of people on our Earth. Our Earth orbits the Sun in our Solar System. Our Sun is one star among the billions in the Milky Way Galaxy. Our Milky Way Galaxy is one among the billions of galaxies in our Universe.

Explanation:

You might be interested in

3. A student adds 0.400g of n-propanol to 13.0 g of t-butanol. What is the molality of the solution? Show your calculations. (3

marissa [1.9K]

Answer:

$m=0.512m$

Explanation:

Hello,

In this case, we can consider the n-propanol as the solute (lower amount) and the t-butanol as the solvent (higher amount), for which, initially, we must compute the moles of n-propanol (molar mass = 60.1 g/mol) as shown below:

$n_{solute}=0.400g*\frac{1mol}{60.1g0}=6.656x10^{-3}mol$

Since the molality is computed via:

$m=\frac{n_{solute}}{m_{solvent}}$

Whereas the mass of the solvent is used in kilograms (0.0130g for the given one). Thus, we compute the resulting molality of the solution:

$m=\frac{6.656x10^{-3}mol}{0.0130kg}\\ \\m=0.512\frac{mol}{kg}$

Or just:

$m=0.512m$

Best regards.

8 0

3 years ago

If you place an item that is 2g/cm3 in a glass of water, will the object float or sink?

Phantasy [73]

It will sink in that glass of water.
as, it's density is more than density of water.

you might be known that the density of water is 1g/cm^2 and it's given that the density of the item is 2g/cm^2,
and
An object only floats in water if it's density is less than that of water so,
that item is going to sink.

8 0

3 years ago

A sample of gas occupies a volume of 450.0 ML at 740 mm Hg and 16c determine the volume of this sample at 760mm Hg and 37C show

algol13

Answer:

474.92 mL.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have two different values of (P, V and T):

P₁V₁T₂ = P₂V₂T₁

P₁ = 740 mmHg, V₁ = 450 mL, T₁ = 16°C + 273 = 286 K.

P₂ = 760 mmHg, V₂ = ??? mL, T₂ = 37°C + 273 K = 310 K.

∴ V₂ = P₁V₁T₂/P₂T₁ = (740 mmHg)(450 mL)(310 K)/(760 mmHg)(286 K) = 474.92 mL.

5 0

3 years ago

Read 2 more answers

Nitroglycerin, used both in medicine and as an explosive, can be prepared by the carefully controlled reaction of glycerol (C3H8

vesna_86 [32]

The mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

We'll begin by calculating the mass of HNO₃ that reacted and the mass of C₃H₅N₃O₉ produced from the balanced equation. This can be obtained as follow:

C₃H₈O₃ + 3HNO₃ —> C₃H₅N₃O₉ + 3H₂O

Molar mass of HNO₃ = 1 + 14 + (16×3)

= 1 + 14 + 48

= 63 g/mol

Mass of HNO₃ from the balanced equation = 3 × 63 = 189 g

Molar mass of C₃H₅N₃O₉ = (12×3) + (1×5) + (14×3) + (16 × 9)

= 36 + 5 + 42 + 144

= 227 g/mol

Mass of C₃H₅N₃O₉ from the balanced equation = 1 × 227 = 227 g

<h3>SUMMARY:</h3>

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Finally, we shall determine the mass of HNO₃ that will produce 2.8 g of C₃H₅N₃O₉. This can be obtained as follow:

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Therefore,

2.8 g of C₃H₅N₃O₉ will be produce by = $\frac{2.8 * 189}{227} \\\\$ = 2.33 g of HNO₃

Thus, the mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

Learn more: brainly.com/question/24918379

3 0

3 years ago

Using the periodic table predict which three elements will have similar chemical properties or reactivity

pickupchik [31]

oxygen, sulfur and selenium as they are all in the same group of the periodic table - they are all chalcogens

8 0

3 years ago