<u>Answer:</u> The molarity of anions in the solution is 0.0316 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of iron (II) chloride = 0.10 g
Molar mass of iron (II) chloride = 126.75 g/mol
Volume of solution = 50 mL
Putting values in above equation, we get:
1 mole of iron (II) chloride produces 1 mole of ions and 2 moles of ions
So, concentration of chloride ions (anions) in the solution =
Hence, the molarity of anions in the solution is 0.0316 M