There’s a part two for this but I can’t fit it all in this image, if you know how to do this please help me out. I’m stuck on th
is one, thanks.
1 answer:
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Answer: The change in entropy change when 207 g of toluene boils at is 223
.
Explanation:
It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.
No. of moles =
=
= 2.25 moles
As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.
= 85.725 KJ
Now, we know that the relation between enthalpy change and entropy change is as follows.
=
= 0.223
or, = 223 (as 1 kJ = 1000 J)
Thus, we can conclude that the change in entropy change when 207 g of toluene boils at is 223
.