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lisov135 [29]
3 years ago
14

Polygon Q is a scaled copy of polygon P using a scale factor of 1/2. Polygon Q's area is what fraction of Polygon P's area.

Mathematics
1 answer:
DaniilM [7]3 years ago
4 0

Answer: Polygon Q's area is 1/4 of Polygon P's area

======================================================

Explanation:

Imagine we had a square with side length 8. The area of this square is 8*8 = 64.

Now let's reduce each side of the square by the scale factor 1/2. So each new side is 8*(1/2) = 4. The area of this smaller square is 4*4 = 16.

Comparing the new area (16) to the old one (64), we see that the new area is 16/64 = 1/4 of the old area.

In other words,

new smaller area = (1/4)*(old larger area)

So this is one example to see why (1/2)*(1/2) = 1/4 is the area scale factor based on the linear scale factor of 1/2. In short, (1/2)^2 = 1/4. Whatever the original scale factor is, square it and you'll get the area scale factor.

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Answer:

m= 1/7

Step-by-step explanation:

To solve for slope: y2- y1/ x2- x1 so,

1-2/ -2-5

= -1/ -7

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8 0
3 years ago
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A rectangular floor of area 21.6 m2 is going to be tiled. Each tile is rectangular, and has an area of 288 cm2. An exact number
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Answer:

Area of Floor = 21.6.m²

Area of tile = 288 cm² = 0.0288 m²

No. of tiles = Area of floor/ area of tile

= 21.6/0.0288

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5 0
2 years ago
Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d
wel
The answer is
q + d = 12
0.25q + 0.10d = 2.40


q - the number of quarters
d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40
3 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

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3 years ago
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