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enyata [817]
2 years ago
13

How many coppers of each atom in the products

Chemistry
1 answer:
yarga [219]2 years ago
6 0

Answer:

Explanation:

moler mass of Cu is 63.546 g/mol. Since 63.546 g of copper has 6.022 x 10 power(23) atoms (Avogadro's number). = 9.5 x 10(power)21 atoms of copper.

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How many moles are in 1.23 X 1050 atoms of calcium carbonate, CaCO3?
pav-90 [236]

Answer:

Explanation:1 mole is equal to 1 moles CaCO3, or 100.0869 grams.

8 0
2 years ago
It is possible to prepare ethanol by nucleophilic substitution. For an electrophile, you could choose EtCl, EtBr, or EtI; for a
tensa zangetsu [6.8K]

Answer:

The reactant/reagent that would be most atom economical is EtI (Ethy Iodide) and KOH (potassium oxide) as base

This is because the iodo group are weak base hence they have a good leaving character (i.e they are unstable on their own ) which would increase the rate of reaction and the strong base KOH give the most atom economical  

Explanation:

4 0
3 years ago
The mass of sample A is 100.0 g, then removed it from a graduated
yan [13]

Answer: 25g/ml

Explanation:

Density = 100.0g/ 4.0mL = 25g/mL

3 0
3 years ago
Two gasses in the air that cause rusting
Korolek [52]

Answer:

oxygen and Hydrogen

Explanation:

Oxygen and Hydrogen causes rusting on metals after combining with moisture

6 0
2 years ago
Read 2 more answers
You placed a sample of a hydrate of calcium chloride (CaCl2) in a weighed test tube, and weighed the filled test tube.
ziro4ka [17]

Answer:

1. 5g

2. 2.3g

3. 2.7g

4. 0.02mol

5. 0.13mol

6. 7moles

Explanation:

From the question, the following were obtained:

Mass of empty tube = 13.5g

Mass of empty tube + hydrated salt = 18.5g

Mass of tube + anhydrous salt = 16.2g

1. Mass of empty tube = 13.5g

Mass of empty tube + hydrated salt = 18.5g

Mass of hydrated salt = 18.5 — Mass of empty tube

Mass of hydrated salt = 18.5 — 13.5 = 5g

2. Let us calculate the mass of the anhydrous salt.

Mass of tube + anhydrous salt = 16.2g

Mass of empty tube = 13.5g

Mass of anhydrous salt = 16.2 — Mass of empty tube = 16.2 — 13.5

Mass of anhydrous salt = 2.7g

Now we can calculate the mass of the water evolved as follows:

Mass of water = Mass of hydrated salt — Mass of anhydrous

Mass of water = 5 — 2.7 = 2.3g

3. Mass of empty tube = 13.5g

Mass of anhydrous salt = 16.2 — Mass of empty tube = 16.2 — 13.5

Mass of anhydrous salt = 2.7g

4. MM of CaCl2 = 40 +(2x35.5) = 40 + 71 = 111g

Mass of CaCl2 = 2.7g

Number of mole = Mass /Molar Mass

Number of mole of CaCl2 = 2.7/111 = 0.02mol

5. MM of H2O = (2x1) +16 = 2 + 16 = 18g/mol

Mass of H2O = 2.3g

Number of mole = Mass /Molar Mass

Number of mole of H20 = 2.3/18 = 0.13mol

6. To get the mole of water in the molecular formula, we will find the ratio of the number of mole of anhydrous salt to water as shown below:

Mole anhydrous : mole of water ie

0.02 : 0.13 = 1 : 7

Therefore, the mole of water in the formula is 7 ie

CaCl2.7H20

3 0
3 years ago
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