Question

If a sample contained 2.33x10^23 atoms of tellurium, (element 52) how many grams would this be

Answer 1

Given the number of atoms or molecules, we need to use Avogadro's number, but first, let's review this concept: The number 6.02×10^(23 ) is called Avogadro's number, the number of representative particles in a mole or atom.

Remember that the symbol of tellurium is Te. Now, doing the conversion to moles we're going to obtain:

$2.33\cdot10^{23}atoms\text{ Te}\cdot\frac{1\text{ mole}}{6.02\cdot10^{23}\text{atoms}}=0.387\text{ moles Te.}$

With this number, we can obtain the grams of tellurium using the molar mass that you can find in the periodic table which is 127.6 g/mol. The conversion from moles to grams will be:

$0.387\text{ moles Te}\cdot\frac{127.6\text{ g Te}}{1\text{ mol Te}}=49.38\text{ g Te.}$

So, 2.33 x 10^(23) atoms of Te are 49.38 of tellurium.