Question

A number cube with the numbers 1 through 6 is rolled. What is the theoretical probability, as a decimal, of the number cube showing a 1? Round the decimal to the nearest hundredth.

Answer 1

Answer:

0.17

Step-by-step explanation:

The numbers are from 1 to 6 on each side.

The total sample space will be 6.

Denoted as:

n(S) = 6

There will be only one outcome as 1

So,

Let A be the event that the number is 1

Then,

n(A) = 1

$P(A) = \frac{n(A)}{n(S)} \\=\frac{1}{6} =0.166$

Hence the theoretical probability of the number cube showing a 1 is 0.166 ..

Rounding off to the nearest hundred

0.17 ..