Answer:
No, because it would be generally free for private-sector employees by using filtering software to restrict access to some websites.
Explanation:
Maria working for the following Corporation, a major private-owned company that specializes throughout ball bearings production. That corporation establishes filtering software to restrict access to some of these sites linked to non-work, and also some sites with poπnographic images.
So, Maria could not challenge that policy lawfully, as private-sector employees are usually free to always use filtering software to restrict access to some of these Websites
Answer:
<em> </em><em>I </em><em>think</em><em> </em><em>text </em><em>and </em><em>pictures</em><em> </em><em>because</em><em> </em><em>I </em><em>know </em><em>it </em><em>is </em><em>in </em><em>my </em><em>book </em><em>I </em><em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em> have</em><em> a</em><em> great</em><em> day</em><em> bye</em><em> and</em><em> Mark</em><em> brainlist</em><em> if</em><em> the</em><em> answer</em><em> is</em><em> correct</em><em> </em>
<em>
</em>
<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on </em><em>learning</em>
The answer is B, look ahead and keep your eyes moving
Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
