If the polynomial is of the form x^2+bx+c (ie., no factor in front of the x^2!!) then you can look for numbers that add up to b and multiply to c.
So in this case: what two numbers, when added, give -2 and when multiplied, give 1? A little trial and error gives you -1 and -1.
So the factorization is (x-1)(x-1). This is zero for x=1. There is only one zero.
Answer:
x+9=4x-4
=) x -4x = -4-9
=) -3x = -13
=) x = 13/3
It is not the form of ax 2 +bx +c =0
Answer:
Always multiply or divide the absolute values
Step-by-step explanation:
Answer:
1/15
Step-by-step explanation:
(1/5) / (3/1)
idk how to explain this but you cross multiply (so 1*1 and 3*5)
Three and Six are the only vertical angles shown above. Hope this helps. :P
