All categories

3 years ago

What is the distance between (14,4) and (15,8)

Mathematics

1 answer:

olasank [31]3 years ago

4 0

=sqrt((x2-x1)^2+(y2-y1)^2)=sqrt((15-14)^2+(8-4)^2)=sqrt(1+16)=sqrt(17)=4.123105625617661=4.1231

You might be interested in

Pick which one doesn't belong. Explain how the answer you chose is different from the other choices.

egoroff_w [7]

Answer:

I think 54 because it's not a squared number

Step-by-step explanation:

8x8=64

9x9=81

12x12=144

5 0

3 years ago

In the expression 852.763 x 10?, what is the missing exponent that would result in a number that is 1,000 times the value of 852

Molodets [167]

Answer:

The missing exponent = power of 3

852.763 x 10³ = 852763

Step-by-step explanation:

The expression 852.763 x 10?

A number that is 1,000 times the value of 852.763 is calculated as:

852.763 × 1000 = 852763

Converting this to exponent

852.763 × 10³ = 852763

Therefore, the missing exponent that would result in number that is 1,000 times the value of 852.763 is power of 3 meaning 10³

7 0

3 years ago

Can someone please explain the area of a circle in the simplest way possible, no links

AlekseyPX

So, for the area of a circle, there should be a line in the middle. Correct?

Well, that line is the diameter. Then cut that in half, so if the diameter is 6, the radius is 3.

Then multiply the the radius by the radius, so 3x3 once you get that, multiply the answer by pi. Pi= 3.14, so if you do 3x3x3.14 you should get 28.26. Hope this helps.

3 0

3 years ago

Write the equation in slope intercept form. what is the slope and y intercept. -9x+10y=-9

Svet_ta [14]

Slope-Intercept Form: y = mx + b, with m = slope and (0,b) as the y-intercept.

So firstly, add both sides by 9x: $10y=9x-9$

Next, divide both sides by 10 and <u>your slope-intercept form is $y=\frac{9}{10}x-\frac{9}{10}$ </u>

Now looking at our slope-intercept form equation, <u>the slope is 9/10 and the y-intercept is (0, -9/10).</u>

5 0

3 years ago

How do i solve this

tensa zangetsu [6.8K]

$5.\\5^\frac{1}{4}\cdot5^\frac{1}{4}\cdot5^\frac{1}{4}=5^{\frac{1}{4}+\frac{1}{4}+\frac{1}{4}}=5^\frac{3}{4}=\sqrt[4]{5^3}=\sqrt[4]{125}\\\\/\text{used:}\ a^n\cdot a^m=a^{n+m}/\\6.\\\left(5^\frac{1}{4}\right)^6=5^{\frac{1}{4}\cdot6}=5^{\frac{1}{2}\cdot3}=5^\frac{3}{2}=5^{1\frac{1}{2}}=5\sqrt5\\\\/\text{used:}\ (a^n)^m=a^{n\cdot m}/$
$7.\\5^{-\frac{1}{4}}=\dfrac{1}{5^\frac{1}{4}}=\dfrac{1}{\sqrt[4]5}\\\\/\text{used:}\ a^{-n}=\dfrac{1}{a^n}/\\8.\\5^2\cdot5^\frac{1}{4}=5^{2+\frac{1}{4}}=5^{2\frac{1}{4}}=5^\frac{9}{4}=5^2\sqrt[4]5=25\sqrt[4]5$

$a^\frac{m}{n}=\sqrt[n]{a^m}$

3 0

3 years ago