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lesya [120]
3 years ago
13

Write a polynomial f(x) that satisfies the given conditions, Express the polynomial with the lowest possible leading positive in

teger coefficient
Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 5-8i and 0 (multiplicity 4).
Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0

9514 1404 393

Answer:

  f(x) = x^6 -10x^5 +89x^4

Step-by-step explanation:

For a given zero p with multiplicity n, one of the factors of the polynomial will be (x -p)^n. If the polynomial has real coefficients, then the complex zeros come in conjugate pairs.

The factored form of your polynomial is ...

  f(x) = (x -(5 -8i))(x -(5 +8i))(x -0)^4

  f(x) = ((x -5)^2 -(8i)^2)(x^4) = (x^2 -10x +89)(x^4)

  f(x) = x^6 -10x^5 +89x^4

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Can someone answer this question,please?
amid [387]
He spent $8.14 on the apples in total. Multiple 2.20 and 2.5 to get 5.5 and then multiply 2.20 by 1.2 to get 2.64. Add up 5.5 and 2.64 to get 8.14
6 0
4 years ago
How many ounces are in 5 gallons?
Serhud [2]

Answer:

640

Step-by-step explanation:

there is 1 gallon for every 128 ounces

so 1 gal= 128z

to find 5gal= ?oz

you multiply 128 by 5 which gives u 640

which gives u 640 oz

hope this helps

6 0
3 years ago
Read 2 more answers
A pair of fair dice is cast. what is the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one
WITCHER [35]
If a pair of fair dice is cast, the probability that the <span>sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is given by:

\frac{P(sum\, of\, 9\, \cup\,3)}{P(3)}

The number of outcomes of sum of 9 where at last one is 3 is (3, 6) and (6, 3) = 2.

</span>The number of outcomes of last one of the numbers falling uppermost is a 3 is (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (1, 3), (2, 3), (4, 3), (5, 3) and (6, 3) = 11.

Therefore, <span>the probabiliy that the sum of the numbers falling uppermost is 9, given that at least one of the numbers falling uppermost is a 3 is 2 / 11.</span>
5 0
4 years ago
Solve 10y4+6y2-12y3-5y4
Olin [163]

Answer:

(5y² - 12y + 6) y²

Step-by-step explanation:

i'm going to assume that you mean to simplify the expression:

10y⁴+6y²-12y³-5y⁴   (group like terms)

= (10y⁴- 5y⁴) - 12y³ + 6y²

= 5y⁴ - 12y³ + 6y²   (factor out y²)

= (5y² - 12y + 6) y²

4 0
4 years ago
(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y<br>{-2, 1}<br>{-2, 3}<br>{}
vaieri [72.5K]

Answer:

{-2, 1}

Step-by-step explanation:

\frac{y+4}{2y} +\frac{y-2}{3} =\frac{3y^2+10}{6y}

Make the fractions have a common denominator.

\frac{3}{3} (\frac{y+4}{2y}) +\frac{x}{y} (\frac{y-2}{3}) =\frac{3y^2+10}{6y}\\\frac{3y+12}{6y} +\frac{2y^2-4y}{6y} =\frac{3y^2+10}{6y}\\\frac{2y^2-y+12}{6y} =\frac{3y^2+10}{6y}

Now that both sides of the equation have a common denominator, you can cancel out the denominators.

2y^2-y+12=3y^2+10

Now, set the equation equal to zero and factor.

2y^2-y+12=3y^2+10\\-y^2-y+2=0\\(-y-2)(y-1)=0\\\\-y-2=0\\y=2\\\\y-1=0\\y=-1

The y-values are {-2, 1}

6 0
3 years ago
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