For a given zero p with multiplicity n, one of the factors of the polynomial will be (x -p)^n. If the polynomial has real coefficients, then the complex zeros come in conjugate pairs.
You have to first get the x by its self by canceling it out so subtract 3 and what you do to one side you do to the other. so that means that -3(-3) two negatives = a positive so thats 6 so what you should have now is x+6