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3 years ago

The area of the shape below I NEED HELP NOW

Mathematics

2 answers:

rewona [7]3 years ago

8 0

Answer:

<h2>10 units ${}^{2}$ </h2>

Step-by-step explanation:

Area of quadrilateral:

$\frac{1}{2} (b1 + b2)h$

Where, b1 = 2 , b2 = 2+2+4 = 8 , h = 2

Now,

$\frac{1}{2} (b1 + b2)h$

plugging the values

$\frac{1}{2} \times (2 + 8) \times 2$

Calculate the sum

$\frac{1}{2} \times 10 \times 2$

Reduce the numbers with G.C.F 2

$= 5 \times 2$

Calculate the product

$= 10 \: {units}^{2}$

Hope this helps...

Best regards!

GalinKa [24]3 years ago

7 0

Answer:

8 units squared

Step-by-step explanation:

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Find the length of the chord made by 3x2 - y2 = 3 and y + x – 5 = 0.

MArishka [77]

Answer:

The correct answer is "9√2 units".

Step-by-step explanation:

The given equations are:

⇒ $3x^2-y^2=3$ ...(equation 1)

⇒ $y+x-5=0$ ...(equation 2)

According to the 2nd equation, we get

⇒ $y+x-5=0$

⇒ $y=5-x$

On substituting the value of "y" in the 1st equation, we get

⇒ $3x^2-y^2=3$

$3x^2-(5-x)^2=3$

$3x^2-(25+x^2-10x)=3$

$2x^2+10x-28=0$

On taking common, we get

$x^2+5x-14=0$

On applying factorization, we get

$x^2+7x-2x-14=0$

$x(x+7)-2(x+7)=0$

$(x+7)(x-2)=0$

$x+7=0$

$x=-7$

or,

$x-2=0$

$x=2$

Now,

The points are:

(-7, 12) = (x₁, y₁)

(2, 3) = (x₂, y₂)

By using the distance formula, the length of chord will be:

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

On substituting the values in the above formula, we get

= $\sqrt{(2-(-7))^2+(3-12)^2}$

= $\sqrt{(9)^2+(-9)^2}$

= $\sqrt{81+81}$

= $9 \sqrt{2}$ units

8 0

2 years ago

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nordsb [41]

Answer:

4/1/4

Step-by-step explanation:

48÷6

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=4/1/4

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Answer:

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umka21 [38]

Answer:

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Step-by-step explanation:

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3 years ago

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