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Tpy6a [65]
2 years ago
15

How many feet are in 57 miles

Mathematics
2 answers:
Licemer1 [7]2 years ago
8 0
300960 is the answer
mezya [45]2 years ago
7 0

Answer:

300960

Step-by-step explanation:

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We are given arc KL is 12x+4, arc KJ is 8x-6, and angle E is 99 degrees. What is the actual degree measure of arc KJ? *
Goryan [66]

Answer:

I think its 20x - 2 because when u are given KJ or KL we need the measurement of x

4 0
2 years ago
Dylan is saving for a new computer and has saved $213. He is saving a $3 a day and needs no more than $654 for the computer he w
shutvik [7]

Answer:

147

Step-by-step explanation:

654 = 213 + 3x

-213    -213

441 = 3x

/3       /3

147 = x

4 0
3 years ago
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0.87 written as a fraction is _____. <br><br> options: 8 over 8<br> 79 over 90<br> 81 over90
atroni [7]
It’s actually 87/100. It couldn’t be one of those answers that you listed...
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2 years ago
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the length of a rectangle is 5 meters less than 3 times the width. the perimeter of the rectangle is 14 meters. find the length
morpeh [17]

Answer:

(4+x) + x = 18; 2x=14; x=7; width = 7, length = 11

Step-by-step explanation:

5 0
2 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
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