How much liquid volume can a soup spoon hold?

Mathematics

1 answer:

KIM [24]3 years ago

5 0

The most a soup spoon could hold is 3-7 mL.

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What is the circumference of each circle? Use 3.14 for PIE. Round to the nearest tenth if necessary.

maksim [4K]

The answer is D 56.5

6 0

2 years ago

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Christina goes to market with $50. She buys one papaya for $20 and spends the rest of the money on bananas. Each banana costs $6

maria [59]

$x-\ number\ of\ bananas\\\\
20+6x\leq50\ \ \ \ | subtract\ 20\\\\
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2 years ago

If cos(x)=1/4 what is sin(x) and tan(x)

anygoal [31]

You can use the identity
cos(x)² +sin(x)² = 1
to find sin(x) from cos(x) or vice versa.

(1/4)² +sin(x)² = 1
sin(x)² = 1 - 1/16
sin(x) = ±(√15)/4

Then the tangent can be computed as the ratio of sine to cosine.
tan(x) = sin(x)/cos(x) = (±(√15)/4)/(1/4)
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There are two possible answers.
In the first quadrant:
sin(x) = (√15)/4
tan(x) = √15

In the fourth quadrant:
sin(x) = -(√15)/4
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3 0

3 years ago

Find the radius of the circle with equation x²+y²+8x+8y+28=0

galina1969 [7]

<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^{2}+y^{2}+8x+8y+28=0$

So, solving we have:

$x^{2}+y^{2}+8x+8y=-28$

$(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4$