Solution :
2a + 2b = 7 ...1)
4a + 3b = 12 ...2)
In equation, 1)
a = (7 - 2b)/2 ...3)
Putting value of a in equation 2) we get :
4 × (7 - 2b)/2 + 3b = 12
2( 7 - 2b ) + 3b = 12
14 - 4b + 3b = 12
b = 2
Putting value of b in 3) we get :
a = ( 7 - 2×2)/2
a = 3/2 = 1.5
Now,
2x - 3y = 16 ...5)
x + 2y = -6 ...6)
x = -6 - 2y
Putting above value of x in eq 5) , we get :
2( -6 - 2y ) - 3y = 16
-12 - 4y - 3y = 16
7y = -28
y = -4
x = -6 - ( 2× -4 )
x = 2
Hence, this is the required solution.
Answer:
20
Step-by-step explanation:
Replace the variables with their corresponding numbers.
y-x/z 64-4/3 60/3 20
ΔACD and ΔASR are the same so we can write a ratio:
x/4 = 10/5
x/4 = 2
x/4 * 4 = 2 * 4
x = 8
Since AS is equal to x, they are both the same.
Therefore, the answer is [ x = 8, AS = 8 ]
Best of Luck!
16 1/3 is bigger than 1/4
