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wlad13 [49]
3 years ago
8

A person is pushing two carts that are connected with a metal bar so that the carts are moving at constant acceleration 0.30m/s2

. The masses of the carts are 100 kg and 150kg, and the mass of the connecting bar is 60 kg. Assume that the friction forces are negligible. Also assume that you are pushing the lighter cart to the right. A) Determine the force that the bar exerts on the lighter cart. B) Determine the force that the heavier cart exerts on the bar.
Physics
1 answer:
madreJ [45]3 years ago
6 0

Answer:

63N, 45N

Explanation:

Given:

Tension 1 = T1

We have the following free body equations:

F - T1 = 100*0.3 -(I)

T1 - T2 = 60*0.3 -(II)

T2 = 150*0.3 -(III)

Adding the three above equations, we have

F - T1 + T1 - T2 + T2 = (100*0.3) + (60*0.3) + (150*0.3)

Hence, F = 93N

Hence, substituting into equation I we have

T1 = Force by bar on lighter cart = 93 - (100*0.3) = 63N

Hence, force that heavier cart exerts on bar

T2 = 150*0.3 = 45N

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A 44-turn rectangular coil with length ℓ = 17.0 cm and width w = 8.10 cm is in a region with its axis initially aligned to a hor
Mumz [18]

Answer:

The maximum induced emf in the rotating coil  = 29.66V

The induced emf in the rotating coil when (t = 1.00 s) = 26.66V

The maximum rate of change of the magnetic flux through the rotating coil = 0.674Wb/s

Explanation:

Lets state the parameters we are being given right from the question:

Number of rectangular coil, (N) = 44

Length of Coil, l =17cm in meters we have; (l) = 17 × 10⁻² m

Width of Coil, w =8.10cm in meters we have; (w) = 8.10 × 10⁻² m

Magnitude of Uniform Magnetic Field (B) = 767mT= 765 × 10⁻³ T

Angular Speed of Coil, (ω) = 64 rad/s

(a)

To calculate the induced emf in the rotating cell,we can use the formula:

emf = NBAωsin(ωt)

For maximum induced emf, the value of sin(ωt) will be 1

emf_max = NBAω ; if (A = l × w) , we have:

emf_max  = NB(l × w)ω

subsitituting the parameters into the above equation; we have:

emf_max  = 44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64

= 29.66V

(b)

At t = 1s, the induced emf is calculated as:

emf = NBAωsin(ωt)

substituting the parameters into the equation, we have:

emf =   44 × 765 × 10⁻³ ( 17 × 10⁻² × 8.10 × 10⁻² ) × 64 × sin (64 × 1)

=26.66V

(c)

To calculate the maximum rate of change of the magnetic flux through the rotating coil; we need to reflect on the equation for the maximum induced emf in terms of magnetic flux.

i.e emf_max = N\frac{d∅}{dt}

since emf_max = 29.66 and N = 44; we have:

29.66 =  44\frac{d∅}{dt}

\frac{d∅}{dt} = \frac{29.66}{44}

= 0.674 Wb/s

5 0
4 years ago
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