Answer:
0.5sec
Explanation:
Parameters
Height(H) =20m
Initial velocity(u) = 5m/s
Acceleration due to gravity(g) =10m/s^2
Method one
Using the second law of motion
H=ut-1/2gt^2
20=5t-1/2×10×t^2
20=5t-5t^2
dh/dt = 5-10t
where any constant is zero therefore the 20 is zero
5-10t=0
Collect like terms
-10t= -5
t=1/2 = 0.5sec
2nd method
Parameters
Height(H) =20m
Initial velocity(u) = 5m/s
Acceleration due to gravity(g) =10m/s^2
Using the time taken formula
t=u/g
t=5/10
t=0.5sec
Answer:
A. kinetic energy
B. angular velocity
E. angular position
Explanation:
The quantities that cannot be constant if a constant net torque is exerted on an objecta are:
A. Kinetic energy. If a torque is applied, the linear or angular speed will be changing at a rate proportional to the torque, so the kinetic energy will change too.
B. Angular velocity. It will change at a rate equal to the torque.
C. Angular position. If the angular velocity changes, the angular position will change.
D = 1/2gt^2 <-- free fall formula
d = (0.5)(9.81)(1.5^2)
d = 11.03625
d = 11.04 m
hope this helps and have a great day :)
