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Ilya [14]
2 years ago
11

Fluid originally flows through atube at a rate of 200 cm3/s. Toillustrate the sensitivity of the Poiseuille flow rate to various

factors, calculate the new flowrate for the following changes with all other factors remaining the same as in the original conditions: A new fluid with 6.00 times greater viscosity is substituted. Poiseuille flow is given by:
Physics
1 answer:
Alexxx [7]2 years ago
3 0

Answer:

Q_{2}=1200cm^{3}/s

Explanation:

Given data

Q₁=200cm³/s

We know that:

F=n\frac{vA}{l}\\

can be written as:

ΔP=F/A=n×v/L

And

Q=ΔP/R

As

n₂=6.0n₁

So

Q=ΔP/R

Q=\frac{nv}{lR}\\ \frac{Q_{2}}{n_{2}}= \frac{Q_{1}}{n_{1}}\\ Q_{2}=\frac{Q_{1}}{n_{1}}*(n_{2})\\Q_{2}=\frac{200}{n_{1}}*6.0n_{1}\\ Q_{2}=1200cm^{3}/s

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Answer:

(a) Time t = 16.46 sec

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Explanation:

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Final speed v = 80 km/hr

80km/hr=\frac{80\times 1000}{3600sec}=22.22m/sec

From first equation of motion v =u+at

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(b) Now initial speed u = 22.22 m/sec

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(c) We have given that initial velocity = 80 km/hr = 22.22 m/sec

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Time t = 8.30 sec

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Given that:

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