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2 years ago

Find the moment of force of 60 Newton about an axis of rotation at distance 20 cm from the force

Physics

1 answer:

777dan777 [17]2 years ago

8 0

Answer:

10 N.m

Explanation:

Force * Perpendicular distance.

= 20 N * 0.5 m

= 10 N.m

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In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it, causing the victim to land

Travka [436]

Answer:

A)247.4kgm/s b) 3299.0N

Explanation:

The potential energy of the victim = mgh where m is mass, g is acceleration due to gravity and h is height from where the victim fell

Pe = 79*9.81*0.5 = 1/2mv2 (kinetic energy of the motion) v is speed in m/s

v = √9.81 = 3.132m/s

Change in momentum of the victim = m(vi-vf)

Vi is zero and vf is the velocity of impact

Change in momentum = 79*(3.132-0) = 247kgm/s which also the impulse

B) average force x time = impulse = 247

Average force = 247/0.075 = 3299.04N

5 0

2 years ago

Two workers are sliding 470 kg crate across the floor. One worker pushes forward on the crate with a force of 450 N while the ot

nydimaria [60]

Answer:

0.169

Explanation:

There are three forces acting on the crate along the horizontal direction:

- The pushing force of the first worker, F1 = 450 N forward

- The pushing force of the second worker, F2 = 330 N forward

- The frictional force $F_f$ acting backward

The crate slides with constant speed, so its acceleration is zero: a = 0. This means that we can write Newton's second law as

$\sum F = ma = 0\\F_1 + F_2 - F_f = 0$

The frictional force can be rewritten as

$F_f = \mu mg$

where

$\mu$ is the coefficient of kinetic friction

m = 470 kg is the mass of the crate

g = 9.8 m/s^2 is the acceleration due to gravity

Substituting everything into the previous equation, we find:

$F_1 + F_2 - \mu mg = 0\\\mu = \frac{F_1 + F_2}{mg}=\frac{450 N+330 N}{(470 kg)(9.8 m/s^2)}=0.169$

8 0

2 years ago

Find the mass of a football player who weighs 1250 n.

NISA [10]

We know, W = m * g
1250 = m * 9.8
m = 1250 / 9.8
m = 127.55 KG

In short, Your Answer would be 127.55 Kg

Hope this helps!

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2 years ago

1. Vervollständige den Lückentext.

ICE Princess25 [194]

Answer:

SUP

Explanation:

4 0

2 years ago

Which of the following represents an image that is located in front of a lens?

Lostsunrise [7]

-di represents an image in front of a lens

5 0

2 years ago

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Find the moment of force of 60 Newton about an axis of rotation at distance 20 cm from the force​

Find the moment of force of 60 Newton about an axis of rotation at distance 20 cm from the force